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Anna007 [38]
3 years ago
11

Which is an estimate of LaTeX: \sqrt{14} 14 to the nearest hundredth?

Mathematics
2 answers:
Mariana [72]3 years ago
6 0

Answer:

3.74

Step-by-step explanation:

Square root of a number is the number that multiplies by itself to result in, in this case, 14.  The number is irrational, often, though here is close to 3.74, according to the calculator.  Many, though not all, courses recommend calculators for determining square roots, as the mathematical process is quite complex and often not taught.  Try this if your course allows, and if not, wow that's a tough course.  

polet [3.4K]3 years ago
4 0

Answer:

3.74

Step-by-step explanation:

The square root of 14 is between the square root of 9 and the square root of 16, so it is between 3 and 4. However, since 14 is much closer to 16 than it is to 9, the square root of 14 will also be closer to 4 than 3. So, a pretty accurate estimation would be 3.74.

Hope this helped! :)

You might be interested in
What is the exact value of <img src="https://tex.z-dn.net/?f=tan%5Cfrac%7B11%5Cpi%20%7D%7B12%7D" id="TexFormula1" title="tan\fra
AnnyKZ [126]

Notice that

11/12 = 1/6 + 3/4

so that

tan(11π/12) = tan(π/6 + 3π/4)

Then recalling that

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

⇒   tan(x + y) = (tan(x) + tan(y))/(1 - tan(x) tan(y))

it follows that

tan(11π/12) = (tan(π/6) + tan(3π/4))/(1 - tan(π/6) tan(3π/4))

tan(11π/12) = (1/√3 - 1)/(1 + 1/√3)

tan(11π/12) = (1 - √3)/(√3 + 1)

tan(11π/12) = - (√3 - 1)²/((√3 + 1) (√3 - 1))

tan(11π/12) = - (4 - 2√3)/2

tan(11π/12) = - (2 - √3) … … … [A]

8 0
2 years ago
Do the ratios 8/ 5 and 11 /6 form a proportion?
nordsb [41]

Answer:

no they don't

hope this helps

have a good day :)

Step-by-step explanation:

4 0
3 years ago
Estimating the quotient 57.8 divided 81
rodikova [14]
It would be.703 i think hope this helps
5 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
Help plz i need some one two help me
mario62 [17]
I forgot how to do this
5 0
3 years ago
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