The answer is 5. Hope this helps
Answer:
<h2>X=6</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>let's solve:</h3>
Answer:
Step-by-step explanation:
problem 4
Velocity is +2.0m/s and constant acceleration is -0.5m/s^2
For every second the velocity drop by 0.5 m/s, so after 2 seconds the velocity is 1 m/s.
problem 5
Accelerate from rest to 28m/s means go from 0 to 28m/s so with
a constant acceleration of 5.5 m/s^2 it will take 5.09 second
Formula for finding circumference of a circle is 2πr.
Step-by-step explanation:
- The given question says what is the circumference of a circle that is 9cm.
- As radius is required for finding circumference of a circle, the formula is 2πr.
- Therefore taking the formula and substituting radius (r)= 9 cm. We get 2πr as 2×π×9 = 18π cm OR
- If we substitute the value of π as 3.14 we will get⇒ 2×3.14×9= 56.52 cm.
- So the circumference of the given circle would be 18π or 56.52 cms.
Answer:
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
Step-by-step explanation:
The equation for the volume of a pyramid of base area B and height h is
V = (1/3)·B·h. Here, V = 432 ft³, B = (12 ft)² and h (height of the pyramid) is unknown. First we find the height of this pyramid, and then the slant height.
V = 432 ft³ = (144 ft²)·h, so h = (432 ft³) / (144 ft²) = 3 ft.
Now to find the slant height of this pyramid: That height is the length of the hypotenuse of a right triangle whose base length is half of 12 ft, that is, the base length is 6 ft, and the height is 3 ft (as found above).
Then hyp² = (3 ft)(6 ft) = 18 ft², and the hyp (which is also the desired slant height) is hyp = √18, or √9√2, or 3√2 ft.
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
