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dlinn [17]
4 years ago
8

Solve algebraically 8x + 4y = 48 12x + 5y = 21

Mathematics
2 answers:
Lorico [155]4 years ago
7 0

Answer:

x=-\frac{39}{2}\\ y=51

Step-by-step explanation:

8x+4y=48\\12x+5y=21

Let's solve the first equation for x or y. I'll do it for y.

8x+4y=48

Subtract 8x

4y=-8x+48

Divide by 4.

y=-\frac{8}{4}x+\frac{48}{4}\\

Simplify.

y=-2x+12

Now replace the value of y in the second equation for this.

12x+5y=21\\12x+5(-2x+12)=21

Distribute 5

12x-10x+60=21

Subtract 60

12x-10x=21-60

Combine like terms;

2x=-39

Divide by 2.

x=-\frac{39}{2}

Now replace this in any of the equations to find the value of y.

8x+4y=48\\8(-\frac{39}{2})+4y=48\\

8 and 2 can be simplified.

8/2=4

2/2=1

4(-39)+4y=48

Distribute 4.

-156+4y=48

Add 156

4y=48+156\\4y=204

Divide by 4

y=\frac{204}{4}

y=51

Proof:

8x+4y=48\\8(-\frac{39}{2} )+4(51)=48\\4(-39)+204=48\\-156+204=48\\48=48

shtirl [24]4 years ago
5 0
8x+4y=48
-4y -4y
8x=48-4y
divide 8 to both sides

x=6-1/2y


substitute the given value of x into the equation 12x+5y=21

12(6-1/2y)+5y=21

distribute 12 through the parentheses

72-6y+5y=21

add like terms

72-y=21

move constant to the right hand side and change signs

-y=21-72

calculate the difference

-y= -51

change signs

y=51

solve the question for x

x= 6-1/2 x 51

x= -39/2

(x,y) = (-39/2 , 51)
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