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VladimirAG [237]
3 years ago
5

The triangles are similar. What is the value of x? Enter your answer in the box. x =

Mathematics
1 answer:
notsponge [240]3 years ago
6 0

Answer:

Value of x is used to consider unknown value. The letter “x” is commonly used in algebra to indicate an unknown value. It is referred to as a “variable” or, in some cases, a “unknown.” In x + 2 = 7, x is a variable. ... A variable need not be “x,” but might be “y,” "w," or any other letter, name, or symbol.

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Luis starts to do a division problem and notices that there is a pattern in the digits to the right of the decimal point.This nu
Assoli18 [71]

Answer: Rational

Step-by-step explanation:

5 0
3 years ago
how do you solve 2e - 12 = 7e + 8? i got 4 but the answer key says it's -4. what do you subtract from both sides?
ella [17]
First you subtract -2e from both side
7 0
2 years ago
Read 2 more answers
Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>​
Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

    a n d        sin  C =

h

b

or

h = c  sin  B     a n d       h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

=

b

 sin  B

=

c

 sin  C

- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

      a n d          sin  C =

h

b

or

h = c  sin  B       a n d         h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

 sin  C

Combining (4) and (9):

a

 sin  A

=

b

 sin  B

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7 0
3 years ago
Please simplify this please it’s due really soon!
iren2701 [21]

Step-by-step explanation:

\frac{ {13}^{6}  \div  {13}^{8}  \times  {13}^{ - 4} }{ {13}^{ - 2} }

You need to remember the properties of exponents: multiplication adds the exponents, division subtracts the exponents.

If you multiply two powers with the same base, the result will be the base to the sum of the powers.

If you divide two powers with the same base, the result will be the base to the difference of the powers.

In your case you will this:

{13}^{6 - 8 + ( - 4) - ( - 2)}

That is:

{13}^{ - 4}

Or:

\frac{1}{ {13}^{4} }

7 0
3 years ago
What is the value of x in the equation 8 + x = 3?<br><br> A. −5<br> B. 5<br> C. 11<br> D. 24
zlopas [31]

Answer:

I think it's A

I hope this helps

3 0
3 years ago
Read 2 more answers
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