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valkas [14]
2 years ago
15

Which best explains whether a triangle with side lengths 2 in., 5in., and 4in. is an acute triangle?

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
7 0
Yes,  I would say so, or a right triangle.
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Can I factor this polynomial?<br><br> 9pr^2+73pr+70r
egoroff_w [7]
R(9p^2+73p+70)
r(9p+10)(p+7)
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Write the name of the following figure symbalically. PLEASE help!!
horrorfan [7]

There's many different types of shapes and figures. This is called <em>rhombus</em>.

A rhombus is a type of quadrilateral, and always has 4 sides and 4 verticals.

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Mark makes $60 for every six hour shift he works. How much will he make if he works an eight hour shift
Illusion [34]

Answer:

Mark will make $80 if he works an eight-hour shift.

Step-by-step explanation:

For every six hour shift he works, Mark makes $60

This implies that for every hour, he makes $10 ($60/6)

Therefore, for working an eight-hour shift, Mark will make $80 ($10 * 8) or ($60/6 * 8).

We can conclude that Mark's employer pays him $10 per hour.

This hourly rate can be used to work out how much Mark will earn if he works for a month or a year, as the case may be.

7 0
2 years ago
HELP PLEASE IM REALLY STUCK
liberstina [14]
The 15th term will be 71. Why? Well, see below for an explanation!

By subtracting all of these numbers by the term that comes prior to them, we will find that all of them result in 5. Because of this, we know that each time the term increases, 5 is being added to the numbers. Additionally, I noticed that all of the numbers in this arithmetic sequence only end in a 1 or a 6. Because of this, we can apply the same principle when adding 5 each time:

First term: 1
Second term: 6
Third term: 11
Fourth term: 16
Fifth term: 21
Sixth term: 26
Seventh term: 31
Eighth term: 36
Ninth term: 41
Tenth term: 46
Eleventh term: 51
Twelfth term: 56
Thirteenth term: 61
Fourteenth term: 66
Fifteenth term: 71

By adding 5 each time and keeping in mind that the digits all end in only 1 or 6, we will find that the fifteenth term results in 71. Therefore, the 15th term is 71.

Your final answer: The 15th term of this arithmetic sequence comes down to be 71. If you need extra help, let me know and I will gladly assist you.
4 0
2 years ago
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