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Artist 52 [7]
3 years ago
7

r^{2/3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
aksik [14]3 years ago
5 0

Step-by-step explanation:

{r}^{ \frac{7}{8}  +  \frac{2}{3} }

{r}^{ \frac{21 + 16}{24} }

{r}^{ \frac{37}{24} }

Hope it helps:)

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9. Given 8x+4y = 4, identify the slope and y-intercept.
Elden [556K]

Answer:

A) Slope = -2 and y-int = 1

Step-by-step explanation:

The easiest way to get the slope and y-intercept from an equation is to put it in slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.

So, let's subtract 8x from both sides, leaving 4y on the left side:

8x + 4y = 4 -> 4y = -8x + 4

Now, let's divide both sides by 4, so that we can have just y on the left side:

y = -2x + 1

-2 is the slope, and 1 is the y-intercept.

3 0
3 years ago
The circumference of a circle is 11r inches. What is the area, in square inches, of the circle? Express your answer in terms of
ira [324]

Answer:

69.12r square inches

Step-by-step explanation:

C = 2πr

   = 2 x π x 11r

   = 69.12r

3 0
3 years ago
What are the domain and range of the function
atroni [7]

Answer:

Domain (-∞,∞)

Range (0, ∞)

Step-by-step explanation:

The domain of a function is always the set of all real numbers therefore the domain is going to be (-∞,∞). The range is (0, ∞) because 0 is one of the outputs for the function

3 0
3 years ago
Use the definition of a derivative to find f’(x).
tatyana61 [14]

Answer:

f'(x) = -\frac{9}{x^2}

Step-by-step explanation:

i) f(x) = 9 / x

ii) f'(x)  = $\lim_{h\to 0} \frac{f(x+h) - f(x)}{h} $  \hspace{0.2cm}

        = $\lim_{h\to 0} \frac{\frac{9}{x+h}  - \frac{9}{x} }{h}  =  \hspace{0.1cm} $\lim_{h\to 0} \frac{9x - 9(x+h)}{hx(x+h)} $ \hspace{0.1cm} =  \hspace{0.1cm}$\lim_{h\to 0} \frac{-9h}{hx(x+h)}  =  $\lim_{h\to 0} \frac{-h}{x(x+h)} = \frac{-9}{x^2}$

7 0
3 years ago
Hurry please!!! Fast response
AlladinOne [14]

Answer:

A.

SA= \frac{2}{3} \pi rl+16 \pi r^2

Step-by-step explanation:

Surface area of the original cone

SA= \pi r l + \pi r^2... (1)

When, radius is quadrupled and slant height is reduced to one sixth

i. e. \: \:r = 4r\: \: \&\:\: l= \frac{1}{6}l

Plug the above values of r and l in equation (1), new surface area becomes:

SA= \pi (4r)\times \frac{1}{6} l+ \pi (4r)^2

SA= \frac{4}{6} \pi rl+16 \pi r^2

\huge \purple {\boxed {SA= \frac{2}{3} \pi rl+16 \pi r^2}}

8 0
3 years ago
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