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3 years ago

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Mathematics

1 answer:

Dovator [93]3 years ago

4 0

Answer:

The range of the function is [0 , ∞) ⇒ answer B

Step-by-step explanation:

* lets revise the meaning of the domain and the range

- The domain is the values of x

- The domain is all the values of x which make the function is defined

- If there are some values of x make the function undefined, we

exclude these values from the domain

- The range is the values of f(x) which corresponding to the value of x

* Now lets look to the figure

∵ f(x) = √x

- We can not use the negative values for x because there is no

square root for negative numbers

∴ All real negative numbers make the function undefined

- We must exclude them from the domain

∴ The domain is all real numbers greater than or equal zero

∴ x ≥ 0

- To find the range use the first value of the domain

∵ the first value of x = 0

∴ f(0) = √0 = 0

∵ x can not be negative

∵ f(x) = √x

∴ f(x) can not be negative

∴ the range is all real numbers greater than or equal zero

∴ f(x) ≥ 0

f(x) = [0 , ∞)

* The range of the function is [0 , ∞)

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BigorU [14]

Answer:

y = $-\frac{1}{3}$

$2\frac{2}{3}=x$

Step-by-step explanation:

To solve a system of equations, solve one or both of the equations for the same variable. Then multiply one of the equations such that the coefficients of one variable are the additive inverse of the variable in the other equation. After doing so, add the two equations, then solve for the other variable using inverse operations. Finally, substitute the value of the other variable into one of the original equations in the system and solve for the unknown variable.

2x + y = 3

y = x - 2

First, manipulate the first equation such that the equation is solved for (y), this can be done using inverse operations,

y = 3 - 2x

y = x - 2

Now multiply the second equation by (2) so that the (x) coefficients are additive inverses of each other,

y = 3 - 2x

2y = 2x - 4

Add the equations,

3y = -1

Inverse operations,

3y = -1