I'll assume the question is whether the tourists will all fit.
15 vans × 9 tourists each van = 135 tourists can fit so he needs another van or 5 of them have to hold on to the roof of the car
Step-by-step explanation:
= 1/2x^2.12x^2 - 1/2x^2.4x + 1/2x^2.2
= 6x^4 - 2x^2 + x
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
i think this is a systems of equations
putting this on a graph we have to equations:
y = 10x + 30
y = 20x
graph and find the intersection.
it has to be more than or equal to 3 miles i think for wreckomend
the answer is c: .... 72+8w
