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Volgvan
3 years ago
9

The relationship between the number of hours a person practices a task and the time it takes them to complete the task is calcul

ated to have R-sq = 56.7%. The value of the correlation coefficient is
Mathematics
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:  0.753.

Step-by-step explanation:

The value of the correlation coefficient is denoted by 'r'. It is used to describe the strength and direction of the relationship between two variables.

Given: The relationship between the number of hours a person practices a task and the time it takes them to complete the task is calculated to have R-sq = 56.7%.

= 0.567

Then, r=\sqrt{R^2}

=\sqrt{0.567}\approx0.753

Hence, the value of the correlation coefficient is 0.753.

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Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

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a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
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