Its impossible to draw a trapezoid with just three right angles.
a trapezoid has 4 sides, which means all the angles inside the trapezoid must add up to 360 degrees.
if you have just 3 right angles (90x3), you already use up 270 degrees. Leaving you with just 90 degrees left, which is also a right angle. That means, there has to be four, if you have at least 3.
Answer:
10+3pi
Step-by-step explanation:
The perimeter of of the shaded region is
AC+CT+marcSBT+SA
*Finding AC
The diagonals of a rectangle are equal is measurement. Since RB is a radius of the circle, then RB is 6. Since AC and RB are both diagonals of the rectangle, then AC is also 6.
*Finding CT
CT=RT-RC where RC is the width of the rectangle
Also RT is a radius so we have that
CT=6-RC
*Finding marcSBT
The circumference of a whole circle is 2pi*r.
We have a quarter of this with r=6.
1/4*2pi(6)
1/4*12pi
3pi
*Finding SA
SA=RS-AR
RS is a radius of the circle and AR is the length of the rectangle.
So we have that this can be rewritten as
SA=6-AR
Let's put these parts together:
6+6-RC+3pi+6-AR
Simplifying:
18-RC-AR+3pi
18-(RC+AR)+3pi
18-8+3pi (Remember length plus width equal 8)
10+3pi
Slope intercept form:
Y = mx + b
m = slope, b = y intercept
Given the slope of 4
Y = 4x + b
Plug in the point (3,8)
8 = 4(3) + b
8 = 12 + b, b = -4
Y intercept = -4
Solution: y = 4x - 4
To answer your question (PLEASE HELP) Evaluate the expression 2(8 − 4)^2 − 10 ÷ 2.
The answer would be B:27
