All categories

3 years ago

3x+2=11 plz hep im slow in math

Mathematics

1 answer:

stealth61 [152]3 years ago

3 0

Answer:

Step-by-step explanation:

3×3=9+2=11. so 3 is the answer.

You might be interested in

Write the Slope Intercept Form equation of the line that passes through the points (−24,8) and (−12,28).

Step2247 [10]

Answer:

y = 5/3x + 48

Step-by-step explanation:

y2 - y1 / x2 - x1

28 - 8 / -12 - (-24)

20 / 12

5/3

y = 5/3x + b

8 = 5/3(-24) + b

8 = -40 + b

48 = b

4 0

2 years ago

Solve each problem.

Damm [24]

The answer is D. If you need two choices also C.

4 0

3 years ago

in a game, what card would you need to draw to get a score of 0 if you have a (-16), (-35), and 18 in your hand?

m_a_m_a [10]

Answer:

why the negitives

Step-by-step explanation:

in in secod grad

7 0

3 years ago

If 3x-6=21, what is the value of x-2? A. 3 B. 5 c. 7 D. 11

Agata [3.3K]

Answer:

$\large\boxed{c.\ 7}$

Step-by-step explanation:

$3x-6=21\qquad\text{divide both sides by 3}\\\\\dfrac{3x}{3}-\dfrac{6}{3}=\dfrac{21}{3}\\\\x-2=7$

4 0

3 years ago

Phoenix is a hub for a large airline. Suppose that on a particular day, 8000 passengers arrived in Phoenix on this airline. Phoe

Afina-wow [57]

Answer:

Step-by-step explanation:

Hello!

In a day a total of n= 8000 passangers arrived to Phoenix.

1400 of these passangers final destination was Phoenix. (A)

The remaining 6600 passangers were all taking connection flights to other cities. (B)

Due to several flights being late, 430 connecting passengers missed their connecting flight and were delayed in Phoenix. (C)

Of these 430 delayed passengers, 75 were delayed overnight. (D)

If there was one passenger chosend at random:

a) You have to calculate the probability of this passegners final destination to be Phoenix. Symbolically: P(A)

To calculate this probability you have to divide the number of passengers whose final destination was Phoenix by the total number of pasengers:

$P(A)= \frac{1400}{8000} = 0.175$

b) The passangers whose final destination was not phoenix are those taking connection flights, the probability of this event, called B, is calculated dividing the total of connecting passengers by the total of passengers:

$P(B)= \frac{6600}{8000}= 0.825$

c) You need to calculate the probability of "the passenger was connecting and missed the connecting flight"

The amount of passengers that fit this situation are 430 of 8000, so the probability is calculated as:

$P(C)= \frac{430}{8000} = 0.05375 ~= 0.054$

d) Of all 6600 connecting passengers, only 430 missend the flight wich means that 6170 took the connecting flight, the probability of this event "E" is

$P(E)= \frac{6170}{8000}= 0.771$

e) The passenger either had Phoenix as a final destination or was delayed overnight, symbolically:

P(A∪D) = P(A) + P(D) - P(A∩D)

The probability of the passenger being delayed overnight is:

$P(D)= \frac{75}{8000} = 0.009$

The events "A" and "D" are mutually exclusive, this means that they cannot occur both at the same time, so their intersection is void, P(A∩D)= ∅

Then

P(A∪D) = P(A) + P(D) = 0.175 + 0.009= 0.184

f) If using the same data we turn this event into a binomial variable were our success will be "the passenger missed his flight and was delayed overnight" with probability p=0.009 and the sample n= 50

Let's say that the airline should be worried if more than half of the surveyed passengers were delayed overnight then:

P(X>25)= 1 - P(X ≤ 25) = 1 - 0.999999 = 0.000001

The probability of most of the surveyed passenger were delayed overnight is too low so the company should not be worried.

I hope it helps!

5 0

3 years ago