3 years ago

Its my birthday soon, im turning 13 where would a fun place to go to

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

PAINTBALL

Step-by-step explanation:

baherus [9]3 years ago

4 0

Answer:

OOOHHH Happy birthday!!!!

Step-by-step explanation:

All of those sound fun, if you want to do all, maybe ask or have a vote on what your guests would like. Have fun!

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miss Akunina [59]

Answer:

B) $2xln(2)(2^{x^2+2})$

Step-by-step explanation:

$y=2^{x^2+2}$

$y'=\frac{d}{dx}(2^{x^2+2})$

$y'=\frac{d}{dx}(e^{(x^2+2)*ln(2)})$

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$y'=2xln(2)*e^{(x^2+2)(ln(2)}$

$y'=2xln(2)(2^{x^2+2})$

Therefore, $2xln(2)(2^{x^2+2})$ is the slope of the tangent line

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