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masha68 [24]
3 years ago
12

Examine the following table of points, which are all on a certain line.

Mathematics
1 answer:
Lapatulllka [165]3 years ago
4 0

\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} {-2}~~\ast&{4}~~\ast\\ 0&2\\ 1&1\\ {3}~~\ast&{-1}~~\ast\\ \cline{1-2} \end{array}~\hspace{10em} (\stackrel{x_1}{-2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-4}{3-(-2)}\implies \cfrac{-5}{3+2}\implies \cfrac{-5}{5}\implies -1

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Answer:

$8,029.91

Step-by-step explanation:

You have to use the exponential growth equation:

A=P(1+r)^t

Where A is the final amount, P is the initial amount, r is the rate of increase, and t is the time in years. So:

A=6,600(1+0.04)^5

(The rate has to be changed into a decimal)

Then, just plug this equation into a calculator (without the A= part, so just 6,600(1+0.04)^5) and you'll get the answer.

8 0
4 years ago
How many solutions does the equation have?
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Answer: there is only one solution

Step-by-step explanation:

Combine like terms by performing the opposite operation of subtracting 4x on both sides of the equation

The 4x's will cross out on the right

4x - 4x = 0x = 0

On the left:

2x - 4x = -2x

Now the equation looks like:

-2x + 3 = 2

Continue to combine like terms by subtracting 3 on both sides of the equation

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3 - 3 = 0

On the right:

2 - 3 = -1

Equation:

-2x = -1

Isolate x by performing the opposite operation of dividing -2 on both sides of the equation

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-2x ÷ -2 = 1

On the right:

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3 years ago
Read 2 more answers
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3 years ago
A projectile is shot into the air following the path,h(x) = - 5t2 + 20t + 3. At what time will it reach a maximum height? t = 1
kramer

Answer:

t = 2

Step-by-step explanation:

Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.

Recall that the formula for the position of the vertex in a general parabolic function of the form: y(x)=ax^2+bx+c, is given by the expression: x_{vertex}=-\frac{b}{2a}

In our case, the variable "x" is in fact "t", the leading coefficient (a) is -5, and the coefficient for the linear term (b) is 20.

Therefore, the maximum of the path will be when t=-\frac{20}{2(-5)} =\frac{20}{10} =2

7 0
3 years ago
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Answer:

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