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Nataly_w [17]
3 years ago
6

What are the domain an range of the function on the graph ?

Mathematics
1 answer:
ipn [44]3 years ago
8 0
The domain of a function is the x and the range of a function is the y.
When a question asks you to find the domain of a function or the range of a given function, you have to find all the possible x values if domain and all the possible y values if range.
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The graph of a function in the form f(x) a(x - h)2 +k is shown. Use the graph to find an equation for f(x).
seropon [69]
O.K.

(h; k) are the coordinates of the vertex.

On the graph are (3; 4), therefore we have:

f(x)=a(x-3)^2+4

We have the x-intercept (1; 0) → x = 1; y = 0.
Substitute them in the equation:

0=a(1-3)^2+4\\\\0=a(-2)^2+4\\\\4a+4=0\ \ \ |-4\\\\4a=-4\ \ \ \ |:4\\\\a=-1

so. We have the answer:

\boxed{f(x)=-(x-3)^2+4}

8 0
3 years ago
I need help plz<br>urgent​
Yuri [45]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
(12√72) : (4√3)
horrorfan [7]

Answer:

ANS. => none of the above

7 0
4 years ago
Exhibit 10-7 In order to estimate the difference between the average hourly wages of employees of two branches of a department s
Leokris [45]

Answer:

E(x)=1

Step-by-step explanation:

From the question we are told that:

Sample mean 1 \=x_1=$9

Sample mean 1 \=x_2=$8

Sample standard deviation 1 \sigma_1 = $2

Sample standard deviation 1 \sigma_2 = $1

Generally the equation for Point estimate is mathematically given by

E(x)=\=x_1-\=x_2

E(x)=9-8

E(x)=1

8 0
3 years ago
Suppose that a dimension x and the area A of a shape are differentiable functions of t. Write an equation that relates to .
marusya05 [52]

Complete question is;

Suppose that a dimension x and the area A = 2x² of a shape are differentiable functions of t. Write an equation that relates dA/dt to dx/dt.

Answer:

Step-by-step explanation:

Since A = 2x²

Let's differentiate both sides with respect to x.

dA/dx = 4x

Now, we want to find the relationship between dA/dt and dx/dt

dA/dt can be expressed as;

(dA/dt) = (dA/dx) × (dx/dt)

Thus;

dA/dt = 4x(dx/dt)

Thus, the equation that relates dA/dt to dx/dt is;

dA/dt = 4x(dx/dt)

7 0
3 years ago
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