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denis23 [38]
2 years ago
14

Name the following segment or point

Mathematics
1 answer:
babunello [35]2 years ago
5 0

Answer:

The answer would be the third option, segment AS

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Explain why x=4 is not in the domain of the function f(x)=√x-5 ?
lianna [129]

Since we are dealing with a radical then x - 5 ≥ 0, for real values

x = 4 is less than 5 , hence is not in the domain




6 0
2 years ago
How can I write 2,351 and standard form
Ludmilka [50]
Isn't 2,351 the standardized form already?
there is word form: two thousand, three hundred fifty one
there is expanded form: (2* 1000)+ (3*100)+ (5* 10)+ (1* 1)= 2,351
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3 years ago
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Please help give brainliest
natita [175]

Answer:

Step-by-step explanation:

-4,5

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1 year ago
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Celia filled the glasses shown below completely with water. The total amount of water that Celia poured into the glasses is 80 c
bagirrra123 [75]
The height of glass 1 is 7.6
so, you find the volume of glass 2,= 26.376
then you subtract the answer from 80 cubic cm to get the volume of glass 1
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7 0
3 years ago
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Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
3 years ago
Read 2 more answers
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