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2 years ago

Name the following segment or point

Mathematics

1 answer:

babunello [35]2 years ago

5 0

Answer:

The answer would be the third option, segment AS

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Alemu, Tulu, Kassa and Tegitu worked for 4 hours, 6 hours, 5 hours

GaryK [48]

As a group they were paid $1000 after putting in 4+6+5+5 = 20 worker-hours.
$1000/(20 worker-hours) = $50/(worker-hour)
Alemu received 4*$50 = $200
Tulu received 6*$50 = $300
Kassa and Tegitu each received 5*$50 = $250

6 0

3 years ago

(2/5)^-2(-3)^4<br><br> What is the equivalent?

Nikolay [14]

Answer:

-8100

Step-by-step explanation:

(2/5)^-2(-3)^4

Given data

and second term

The first term= (2/5)^-2 and

Second term=(-3)^4

Simplify the first term

(2/5)^-2= 2^-2/ 5^-2= 1/2^2 * 1/5^2

=1/4/ 1/25

=1/4*25/1

=100

Simplify the second term

=(-3)^4

= -81

Hence, 100*81

=-8100

8 0

2 years ago

Write the equation for the quadratic function in the graph

Hoochie [10]

Answer:

${x}^{2} - 16 = 0 \: is \: the \: equation$

Step-by-step explanation:

$x = - 4 \\ or \: x = 4$

$(x + 4) = 0 \: or \: (x - 4) = 0 \\ (x + 4)(x - 4) = 0 \\ open \: the \: bracket$

$x(x - 4) + 4(x - 4) = 0$

${x}^{2} - 4x + 4x - 16 = 0 \\ {x}^{2} - 16 = 0$

6 0

2 years ago

A function and its inverse are shown on the same graph. Which statement describes the relationship between the function and its

Korvikt [17]

Answer:C

Step-by-step explanation:on edge

5 0

3 years ago

Line ℓ1 has the equation

aleksley [76]

Answer:

$\sqrt{2}$ units

Step-by-step explanation:

The Line 1 has equation x + y = 5 ....... (1) , and

Line 2 has equation x + y = 3 .......... (2)

Now, we have to find the perpendicular distance between line 1 and line 2.

We can say that (3,0) is a point on line 2 as it satisfies the equation (2).

Now, the perpendicular distance from point (3,0) to the line 1 will be given by the formula

$\frac{|3 + 0 - 5|}{\sqrt{1^{2}+ 1^{2}}} = \frac{2}{\sqrt{2}} = \sqrt{2}$ units (Answer)

We know that the perpendicular distance from any external point ( $x_{1},y_{1}$ ) to a given straight line ax + by + c = 0 is given by the formula $\frac{|ax_{1} + by_{1} + c|}{\sqrt{a^{2} + b^{2}}}$ .

3 0

3 years ago