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3241004551 [841]

3 years ago

5

How long will it take an investment to double in value if the interest rate is 10% compounded continuously? (round your answer t

o two decimal places.)?

1 answer:

Varvara68 [4.7K]3 years ago

8 0

Assumed
PW as 100
FW as twice PW as 200

answer is 7.27254 years

manually take the log of both sides and solve for n

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Need Help With Classifying Shapes. Simple High School Geometry But I was absent the day we went over it. Thanks!

liraira [26]

Quadrilateral RICE is a rectangle because the lengths of the quadrilateral have 2 sides congruent to each other. Also, RICE has slopes with opposite fractions which make the sides parallel to each other.

8 0

3 years ago

I need help again please

masya89 [10]

Distance=speed times time
distance/time=speed

distance=538
time=9 and 15mins
60mins=1hr
15/60=1/4=0.25

time=9.25hr

distance/time=538/9.25=58.162mph
about 58mph

7 0

2 years ago

Read 2 more answers

Find the value of 216m³ - 8n³ if 6m - 2n=0 and mn=12

mestny [16]

Answer:

0

Step-by-step explanation:

Given that,

6m - 2n=0

=>6m=2n

=>n=3m [divide both side by 2]

& mn=12

Now,

216c - 8n³

= 216m³- 8(3m)³

=216m³- 8 .27m³

=216m³- 216m³

=0

6 0

2 years ago

Are<br> Which pair of angles<br> angles?<br> corresponding

-BARSIC- [3]

Answer:

D. <3 and <7

Step-by-step explanation:

Corresponding angles are angles that are on matching sides and that are cut by a transversal.

Hope this helps!

4 0

2 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago