X axis : -t1 cos 60 + t2 cos 60 = 0
t2 cos 60 = t1 cos 60 ; t2 = t1
Y axis : t1 sin 60 + t2 sin 60 - 150 = 0
since t2 = t1
2t1 sin 60 = 150
t1 ( sqrt(3)/2) = 150/2
t1 = 50 [sqrt(3)]
t2 = 50 [sqrt(3)]
t3 = 150 N
hope this helps
Answer: 4.5
<u>Step-by-step explanation:</u>
First, find the points of intersection by solving the system.
y = x² + 2x + 4
y = x + 6
Solve by substitution:
x² + 2x + 4 = x + 6 ⇒ x² + x - 2 = 0 ⇒ (x + 2)(x - 1) = 0 ⇒ x = -2, x = 1
Now, integrate from x = -2 to x = 1
<em>the bottom of the integral is -2 </em>
= 
= 
= 
= 
= 
= 
= -3 + 1.5 + 6
= 4.5
Answers:
The area for the square on the left is 81m^2. This is found because all sides of this square are the same, so the length and width are the same. Just multiply 9 x 9.
The area for the triangle is 31.5m^2. We find the left side is 9 meters because the triangle shares the same side as the square on the left side. We also find the bottom side is 7 because that is the length of each side of that square because all sides on a square is the same. We then multiply 9 times 7, getting 63, we divide this by 2 because it’s a triangle.
The square on the right has the area of 225 because both length and width is 15.
Answer:
a is the answer
Step-by-step explanation:
a is the answer because the way they are being multiplied are consistent, while the others arent.
Answer: Option C
Step-by-step explanation:
Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:
If 
then the graph of k(x) will be the graph of f(x) displaced vertically b units down.
If then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.
In this case we have
We know that this function has its vertex in point (0,0).
Then, to move its vertex 7 units down we apply the transformation:
.
Then the function k(x) that will have its vertex 7 units below f(x) is
