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3 years ago

3p(2p^2–2) Please do. QUICKLY! y e s

Mathematics

2 answers:

andrew11 [14]3 years ago

7 0

Expand by multiply outside term with each of the inside terms to get
6p^3-6p

katrin2010 [14]3 years ago

6 0

Answer:

$- 6p + 6 {p}^{3}$

Step-by-step explanation:

According to the Product-to-Power Exponential Rule, whenever you multiply terms with exponents and coefficients, you add the exponents:

3p[2p² - 2]

6p³ - 6p

The above answer is written in reverse, but it is the exact same result.

I am joyous to assist you anytime.

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The distance around a circular dance hall room is 135 feet. What is the longest distance around the dance hall?

Naya [18.7K]

Answer: 43feet

Step-by-step explanation:

Perimeter= 135 feet

Since perimeter= 2πr

135 = 2πr

Recall that π = 3.14

135 = 2 × 3.14 × r

135 = 6.28 × r

135 = 6.28r

r = 135/6.28

r = 21.5

d = 2r

d = 2 × 21.5

d = 43 feet

4 0

3 years ago

Read 2 more answers

1. what expression is equivalent to z+6z?

lisov135 [29]

1 is D, 2 I'm not sure, 3 is a and b, 4 is a.

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3 years ago

What is the area of this figure?

Dima020 [189]

Answer:

$220.5 \: {yd}^{2}$

Step-by-step explanation:

Area of the figure = Area of the arc with radius 10 yd and central angle 90° + Area of rectangle with dimensions (10 + 5 - 3 = 12) 12 yd and (7 + 6 - 4 = 9) 9 yd + Area of square with dimension 4yd + Area of rectangle with dimensions 3 yd by 2 yd + Area of triangle with base 3 yd and height (5 + 3 = 8) 8 yd.

$= \frac{90 \degree}{360 \degree} \times 3.14 {(10)}^{2} + 12 \times 9 + {4}^{2} \\ + 3 \times 2 + \frac{1}{2} \times 3 \times 8 \\ \\ = \frac{1}{4} \times 314 + 108 + 16 + 6 + 12 \\ \\ = 78.5 + 142 \\ \\ = 220.5 \: {yd}^{2}$

4 0

3 years ago

A farmer wishes to build a rectangular plot with 800 meters of wire fencing. use calculus to find the maximum area that can be e

Sergio039 [100]

He has to build a square, so 800÷4=200
200²=40 000 m²

6 0

3 years ago

Read 2 more answers

HELPPP!

Anika [276]

Answer:

c. x ≈ 1.71, y ≈ 6.29, z ≈ 60.71

Step-by-step explanation:

You are at a bit of a disadvantage with this problem, because both the hint and the answer choices are incorrect.

The matrix equation is ...

$AX=B\\\\\left[\begin{array}{ccc}-1&1&0\\4&3&0\\1&-7&1\end{array}\right]\left[\begin{array}{c}x&y&z\end{array}\right]=\left[\begin{array}{c}8&12&15\end{array}\right]$

Contrary to what the hint is telling you, the multiplication by the inverse must be on the left:

$A^{-1}AX=A^{-1}B\\\\X=A^{-1}B$

Using appropriate tools to compute the inverse, this becomes ...

$\left[\begin{array}{c}x&y&z\end{array}\right]=\dfrac{1}{7}\left[\begin{array}{ccc}-3&1&0\\4&1&0\\31&6&7\end{array}\right]\left[\begin{array}{c}8&12&15\end{array}\right]\\\\\left[\begin{array}{c}x&y&z\end{array}\right]=\dfrac{1}{7}\left[\begin{array}{c}-12&44&425\end{array}\right]\approx\left[\begin{array}{c}-1.714&6.286&60.714\end{array}\right]$

The closest match is choice C.

6 0

4 years ago