3p(2p^2–2) Please do. QUICKLY! y e s

Mathematics

2 answers:

andrew11 [14]3 years ago

7 0

Expand by multiply outside term with each of the inside terms to get
6p^3-6p

katrin2010 [14]3 years ago

6 0

Answer:

$- 6p + 6 {p}^{3}$

Step-by-step explanation:

According to the Product-to-Power Exponential Rule, whenever you multiply terms with exponents and coefficients, you add the exponents:

3p[2p² - 2]

6p³ - 6p

The above answer is written in reverse, but it is the exact same result.

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Please help me figure out this problem

tiny-mole [99]

Answer:

$f(g(x))=f\left(-\dfrac{3x+21}{5}\right)=x\\\\g(f(x))=g\left(-\dfrac{5}{3}x-7\right)=x$

Step-by-step explanation:

Fill in the given expressions and simplify.

$f(g(x))=f\left(-\dfrac{3x+21}{5}\right)=-\dfrac{5}{3}\left(-\dfrac{3x+21}{5}\right)-7\\\\=\left(-\dfrac{5}{3}\right)\left(-\dfrac{3x}{5}\right)-\left(\dfrac{5}{3}\right)\left(-\dfrac{21}{5}\right)-7\\\\=\dfrac{15x}{15}+\dfrac{5\cdot 21}{3\cdot 5}-7=x+7-7=x$