Answer:
<h2>b = <u>2A</u></h2><h2> h</h2><h2 />
Step-by-step explanation:
A = 1/2 b h
A2 = b h
b = <u>2A</u>
h
Answer:
$13.6
Step-by-step explanation:
Jane bought 3 CDs that were each the same price. So let the price of each CD be ‘x’.
It is given that including sales tax, she paid a total of $45.30.
Also each CD had a tax of $1.50. We need to find out what the price of each CD was before tax.
Since the tax for all 3 CDs was same, the total amount of tax that she paid was:
3 * 1.50 = 4.50
Therefore the total tax on 3 CDs is $4.50
Since we already know the total price she paid for the CDs including taxes, we can find the price of each CD by the following way:
3x + 4.50 = 45.30
3x = 45.30 - 4.50
3x = 40.8
x = 13.6
Therefore the price of each CD before tax is $13.6.
Answer:
The volume is 22.44 cubic inches
Step-by-step explanation:
The formula for the volume of a sphere is
We know the diameter, but we can easily convert this into the radius by dividing it by 2, since the diameter is twice as long as the radius.
3.5/2 = 1.75
Now we can find the volume.
So, the average volume of a clementine is 22.46 cubic inches
The closest option you have is 22.44 so if you round it that should be your answer.
In order to do this, you must first find the "cross product" of these vectors. To do that, we can use several methods. To simplify this first, I suggest you compute:
‹1, -1, 1› × ‹0, 1, 1›
You are interested in vectors orthogonal to the originals, which don't change when you scale them. Using 0,-1,1 is much easier than 6s and 7s.
So what methods are there to compute this? You can review them here (or presumably in your class notes or textbook):
http://en.wikipedia.org/wiki/Cross_produ...
In addition to these methods, sometimes I like to set up:
‹1, -1, 1› • ‹a, b, c› = 0
‹0, 1, 1› • ‹a, b, c› = 0
That is the dot product, and having these dot products equal zero guarantees orthogonality. You can convert that to:
a - b + c = 0
b + c = 0
This is two equations, three unknowns, so you can solve it with one free parameter:
b = -c
a = c - b = -2c
The computation, regardless of method, yields:
‹1, -1, 1› × ‹0, 1, 1› = ‹-2, -1, 1›
The above method, solving equations, works because you'd just plug in c=1 to obtain this solution. However, it is not a unit vector. There will always be two unit vectors (if you find one, then its negative will be the other of course). To find the unit vector, we need to find the magnitude of our vector:
|| ‹-2, -1, 1› || = √( (-2)² + (-1)² + (1)² ) = √( 4 + 1 + 1 ) = √6
Then we divide that vector by its magnitude to yield one solution:
‹ -2/√6 , -1/√6 , 1/√6 ›
And take the negative for the other:
‹ 2/√6 , 1/√6 , -1/√6 ›
