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levacccp [35]
3 years ago
7

(5x + 12) 48° solve for x.

Mathematics
1 answer:
zimovet [89]3 years ago
7 0

Answer: It is 108

Step-by-step explanation:

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???? Help plz ?…. It’s a grade
Aleks [24]

Answer:

Yes it does show a dilation

4 0
3 years ago
What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?
Leona [35]
2(3x - 1) ≥ 4x - 6 | Starting equation
6x - 2 ≥ 4x - 6 | Distribute the 2
2x - 2 ≥ -6 | Subtract 4x from each side
2x ≥ -4 | Add -2 to each side
x ≥ -2 | Divide both sides by 2

So, x must be greater or equal to -2 to be in the solution set.
6 0
3 years ago
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How do i find the circumference of a circle when the given radius is 3 1\2 cm, answers in terms of π
VladimirAG [237]

Answer:

Circumference of circle is 9.42cm.

Step-by-step explanation:

Here we have given that A circle with having radius 3 and 1 / 2 cm. And We need to find circumference of circle.

Formula using

Circumference of circle = π × 2 × radius

substitute the value

Circumference of circle = π × 2 × 3 and 1/2 cm.

cancle the 2

Circumference of circle = π × 3 cm

Using π = 22 / 7

\small \sf \ Circumference \: of \: \: circle = \frac{ 22}{7 }×3 cm \\

\small \sf \ Circumference \: of \:circle = 9.42 cm

Hence, Circumference of circle is 9.42cm.

5 0
3 years ago
Please help!
Serggg [28]
The answer is C) (x - 1)2 = 0.5 

The equation is
-9 + 12x - 6x² = 0
Multiply the following equation by (-1) on the both sides:
9 - 12x + 6x² =0

Now, we will use the method of completing the square:
ax² + bx + c = 0             ⇒ a(x + d)² + e = 0,
where d = b/2a, e = c - b² / 4a

The quadratic equation is: ax² + bx + c = 0
Our equation is:                  6x² - 12x + 9 = 0
so in our equation a = 6, b = -12, c = 9

Now, let's replace it:
d = b/2a = -12/2*6 = -12/12 = -2
e = c - b² / 4a = 9 - (-12)²/4*6 = 9 - 144/24 = 9 - 6 = 3
a(x + d)² + e = 0,
6(x + (-1))² + 3 = 0
6(x - 1)² = 3
(x - 1)² = 3/6
(x - 1)² = 1/2
(x - 1)² = 0.5
4 0
3 years ago
I need help figuring out what I did wrong
rewona [7]

Answer:

D

Step-by-step explanation:

Using the addition formula for sine

sin(a + b) = sinacosb + cosasinb

and the exact values

sin(\frac{\pi }{4} ) = cos(\frac{\pi }{4} ) = \frac{\sqrt{2} }{2} , cos(\frac{\pi }{6}) = \frac{\sqrt{3} }{2} , sin(\frac{\pi }{6}) = \frac{1}{2}

Note that \frac{5\pi }{12} = \frac{\pi }{4} + \frac{\pi }{6} , thus

sin(\frac{5\pi }{12})

= sin(\frac{\pi }{4} + \frac{\pi }{6} )

= sin(\frac{\pi }{4})cos(\frac{\pi }{6} ) + cos(\frac{\pi }{4})sin(\frac{\pi }{6})

= ( \frac{\sqrt{2} }{2} × \frac{\sqrt{3} }{2} ) + ( \frac{\sqrt{2} }{2} × \frac{1}{2} )

= \frac{\sqrt{6} }{4} + \frac{\sqrt{2} }{4}

= \frac{\sqrt{6}+\sqrt{2}  }{4} → D

4 0
3 years ago
Read 2 more answers
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