The area of a triangle is given by the formula
, where B is the base and h is the height. We can rearrange this formula to solve for B.
.
We plug in the given area, 640 square millimeters, and the given height, 32 millimeters.
.
40 mm is our final answer.
Answer: the length of string that been let out to fly the kite this high is 172.89 ft
Step-by-step explanation:
The length of string attached to the kite, the vertical height of the kite above the ground and the ground distance forms a right angle triangle.
With an angle of 57 degrees, the length of the string that is attached to the kite represents the hypotenuse of the right angle triangle.
The height of the kite above the ground represents the opposite side of the triangle
To determine h, the length of the string that has been let out to fly the kite this high, we would apply the
Sine trigonometric ratio which is expressed as
Sine θ = opposite side/hypotenuse
Sin 57 = 145/h
h = 145/Sin57 = 145/0.8387
h = 172.89
Hello there,
We need to remember that Mode means: the number that appears more than others.
18 will be your correct answer because the number 18 appears 2 times. And there is no other number that appears 2 times except 18.
18 is your answer.
~Jurgen
Answer: a) BC = 1386.8 ft
b) CD = 565.8 ft
Step-by-step explanation:
Looking at the triangle,
AD = BD + 7600
BD = AD - 7600
Considering triangle BCD, we would apply the the tangent trigonometric ratio.
Tan θ = opposite side/adjacent side. Therefore,
Tan 24 = CD/BD = CD/(AD - 700)
0.445 = CD/(AD - 700)
CD = 0.445(AD - 700)
CD = 0.445AD - 311.5 - - - - - - - -1
Considering triangle ADC,
Tan 16 = CD/AD
CD = ADtan16 = 0.287AD
Substituting CD = 0.287AD into equation 1, it becomes
CD = 0.445AD - 311.5
0.287AD = 0.445AD - 311.5
0.445AD - 0.287AD = 311.5
0.158AD = 311.5
AD = 311.5/0.158
AD = 1971.52
CD = 0.287AD = 0.287 × 1971.52
CD = 565.8 ft
To determine BC, we would apply the Sine trigonometric ratio which is expressed as
Sin θ = opposite side/hypotenuse
Sin 24 = CD/BC
BC = CD/Sin24 = 565.8/0.408
BC = 1386.8 ft
