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mash [69]
3 years ago
5

John volunteers at the animal shelter on weekends. One Saturday, John unloaded 27 bags of dog food. Each bag weighed 35 pounds.

How many ounces of dog food did John unload?
Mathematics
1 answer:
romanna [79]3 years ago
5 0

Answer:

945 ounces

Step-by-step explanation:

if you read it closley you will find that if you multiply you will get 945 ounces because all you have to do is multipply.

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Use the given facts about the functions to find the indicated limit.
oksian1 [2.3K]

Answer: Option b.

Step-by-step explanation:

 1. You can rewrite it as following:

\lim_{x\to \ -6} 2

This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 2, no matter the value of x.

\lim_{x\to \ -6} 2=2

 \lim_{x\to \ -6} 1

 This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 1, no matter the value of x.

\lim_{x\to \ -6} 1=1

2. Then:

\lim_{x\to \ -6} (f/g)(x)=2/1=2

3. The answer 2.

7 0
3 years ago
Read 2 more answers
Graph the equation
Lisa [10]
To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4


x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)
8 0
2 years ago
Is this less than <br> Greater than<br> Or equal too?
kkurt [141]
The values are equal.

Root 5.76= 2.4

-2.4=-2.4
4 0
3 years ago
What other expression is equivalent as 8x6?
uysha [10]
An equivliant to 8x6 is 6x8
8 0
3 years ago
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A die is rolled 20 times. given that three of the rolls came up 1, five came up 2, four came up 3, two came up 4, three came up
Serjik [45]

Solution:

Number of times a die is rolled = 20

1 - 3=A

2 - 5=B

3 - 4=C

4 - 2=D

5 - 3=E

6 -  3=F

Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times

            = Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes

= 6! × [ 3! × 5! × 4!×2!×3!×3!]

= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]

= 895795200  Ways

8 0
3 years ago
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