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Novay_Z [31]
3 years ago
14

A quadratic function, f(x), and its first differences are shown in the table.

Mathematics
2 answers:
gtnhenbr [62]3 years ago
7 0

Answer:

4

4

4

constant

Step-by-step explanation:

Gnoma [55]3 years ago
4 0

Answer:

first differences,4,4,4,constant

Step-by-step explanation:

did on edge

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ASAP. Look at the picture. Answer choices are: A) the spring has no stretch when a force of 1 pound is applied. B) the spring st
Katyanochek1 [597]

Answer:

D) the spring has a length of 1 inch when no force is applied

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3 years ago
I need help really fast!!!
Helga [31]

Answer:

x=4

if that is what you need hope this helped

Step-by-step explanation:

6 0
3 years ago
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and are independent Gaussian (Normal) random Variables. has mean 13.9 and variance 5.2; has mean 6.9 and variance 3.8. . (a) Cal
omeli [17]

This question is incomplete, the complete question is;

X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)

Answer:

P( W> 10) is 0.1587

Step-by-step explanation:

Given that;

X ⇒ N( 13.9, 5.2 )

Y ⇒ N( 6.9, 3.8 )

W = X - Y

Therefore

E(W) = E(X) - E(Y)

= 13.9 - 6.9 = 7

Var(W) = Var(X) + Var(Y) -2COV(X.Y)

[ COV(X,Y) = 0 because they are independent]

Var(W) = 5.2 + 3.8 + 0

= 9

Therefore

W ⇒ N( 7, 9 )

so

P( W > 10 )

= 1 - P( W ≤ 10 )

= 1 - P( W-7 /3   ≤   10-7 /3 )

= 1 - P( Z ≤ 1 )           [ Z = W-7 / 3 ⇒ N(0, 1)  ]

from Standard normal distribution table, P( Z ≤ 1 )  = 0.8413

so

1 - P( Z ≤ 1 )  = 1 - 0.8413 = 0.1587

Therefore P( W> 10) is 0.1587

8 0
3 years ago
The u.s. department of health and human services collected sample data for 772 males between the ages of 18 and 24. that sample
soldier1979 [14.2K]
The 99% confidence interval for the true mean is given by:

\bar{x}\pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

where: 

\bar{x} is the sample mean = 69.7
\sigma is the standard deviation = 2.8
z_{\alpha/2} is the test statistics = 2.58 for for 99% confidentce interval.
n is the sample size = 772.

Therefore, the 99% confidence interval is:

69.7\pm2.58\left( \frac{2.8}{\sqrt{772}} \right)=69.7\pm2.58(0.1008) \\  \\ =69.7-0.26\leq\mu\leq69.7+0.26 \\  \\ =69.44\leq\mu\leq69.96
6 0
3 years ago
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How do you find the scale factor of a prism?
LenKa [72]

Answer:

To find a scale factor between two similar figures, find two corresponding sides and write the ratio of the two sides. If you begin with the smaller figure, your scale factor will be less than one. If you begin with the larger figure, your scale factor will be greater than one

7 0
3 years ago
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