If the center of a circle is at (3,-6) and the diameter is 10 units, what is the equation for the circle

1 answer:

6 0

Answer:(x-3)^2+(y+6)^2=25

Step-by-step explanation:

Center Of The circle is at (3,-6)

Diameter=10

Radius(r)=10/2

Radius(r)=5

a=3

b=-6

Equation of circle=(x-a)^2+(y-b)^2=r^2

Equation of circle=(x-3)^2+(y-(-6))^2=5^2

Equation of circle=(x-3)^2+(y+6)^2=25

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It should be A, since b=11> acosA

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