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Olenka [21]
3 years ago
11

The area of the rectangle flower bed shown is

Mathematics
1 answer:
sp2606 [1]3 years ago
6 0

Answer:

I think 5.4

Step-by-step explanation:

Take it and divide by the number of sides

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Example of Order of operations
uysha [10]
6/2(1+2)
= 6/2(3)
= 6/6
= 1
3 0
3 years ago
This table shows temperatures in an Arctic city during
ioda

According to the temperature changes, it is found that:

  • On Tuesday, the temperature at Noon was of -28.5 ºF.
  • On Wednesday, the temperature at Midnight was of -5.5 ºF.
  • On Thursday, the change was of -11.8 ºF.
  • On Friday, the temperature at Noon was of -4.5 ºF.

<h3>What is the temperature change?</h3>
  • The temperature change during a period is given by the <u>temperature at the end of the period subtracted by the temperature at the start of the period</u>.

On Tuesday:

  • At the start of the period, the temperature was of -17.5 ºF.
  • The change was of -11 ºF.

Hence:

-11 = T_N - T_M

-11 = T_N + 17.5

T_N = -28.5

On Tuesday, the temperature at Noon was of -28.5 ºF.

On Wednesday:

  • At the end of the period, the temperature was of 10 ºF.
  • The change was of 15.5 ºF.

Hence:

15.5 = 10 - T_M

T_M = -5.5

On Wednesday, the temperature at Midnight was of -5.5 ºF.

On Thursday:

  • At the end of the period, the temperature was of -24 ºF.
  • At the start of the period, the temperature was of -12.2 ºF.

Hence:

C = -24 - (-12.2) = -24 + 12.2 = -11.8

On Thursday, the change was of -11.8 ºF.

On Friday:

  • At the start of the period, the temperature was of -21.8 ºF.
  • The change was of 17.3 ºF.

Hence:

17.3 = T_N - T_M

17.3 = T_N + 21.8

T_M = -4.5

On Friday, the temperature at Noon was of -4.5 ºF.

You can learn more about change at brainly.com/question/24313700

8 0
3 years ago
Calculate the volume of the solid. Round answer to the nearest hundredth.
Ostrovityanka [42]

Answer:

630 ft^3

Step-by-step explanation:

8 0
3 years ago
────────────────────────────────── ────────────██████████──────────── ────────███████████████████─────── ──────█████████████████
Papessa [141]

Answer:

Lol

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

7 0
3 years ago
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