You said worth 20, but it’s worth 10 soo
When A is reflected over y=-1, -1+(-1-(-2))=0, it lands on (-5, 0), when it is then reflected over x=3, 3+(3-(-5))=11, it lands on (11,0)
If you can't visualize it, draw a graph.
Given
Given

SolutionStep 1Find slope


Substitute the given points into the slope formula

step 2Equation of a line


Step 3

The final answerOption B
to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient


Step-by-step explanation:
parallelogram area is:h×base
10×14=140
we have two so
140×2=280
traingle is:h×base/2
18-10=8=h
8×14/2=56
56×3=168
168+280=448