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Elanso [62]
3 years ago
13

1. AB = 11 and BC = 5. Find AC 2. AC = 16, BC = x + 4, AB = x + 14. Find x

Mathematics
1 answer:
lord [1]3 years ago
5 0
The wording of the question kinda doesn't make sense in some parts, but I'll try anyway. 1 plus 4 is 5, and since BC is 5, x is 1 for BC. -3 plus 14 is 11, so x is -3 for AB.
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Akimi4 [234]

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45 dandelion × 15 rows= 675

7 0
2 years ago
Select the angle that correctly completes the law of cosines for this triangle. 72 + 252 – 2(7)(25)cos ___ = 242 A. 180° B. 90°
meriva

Answer:

x =76.45 degrees

Step-by-step explanation:

72 + 252 – 2(7)(25)cos _x__=242

combine like terms

324-350cosx = 242

subtract 324 from each side

-350x = -82

divide by -350

cos x = -82/-350

cos x = 82/350

take the arccos of each side

arccos (cos x) = arccos (82/350)

x =76.45 degrees


7 0
3 years ago
1/10( x + 130) = -2(3-X)<br><br> I need help
Artist 52 [7]

Answer:

x = 10

Step-by-step explanation:

1/10(x + 130) = -2(3 - x)

x + 130 = -20(3-x)

x + 130 = -60 + 20x

x - 20x = -60 - 130

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x = 10

5 0
3 years ago
Which geometric figures have a measurable quantity? A. line B. angle C. point D. lin
Jlenok [28]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
Which set of coefficients of the terms in the expansion of the binomial (x+y)^3 is correct ?
BigorU [14]
We are technically FOILing this out... with a power of 3.

(x+y)(x+y)(x+y)

So we can first factor out the first two "x+y"s.

( x^{2} +2xy + y^{2} ), multiplied by the last "x+y".

x^{3} +3 x^{2} y +3x y^{2} + y^{3}

Coefficients are the number that comes in front of a variable. 

In this case, 1 comes in front of x^{3}, 3 comes in front of x^{2} y, 3 comes in front of x y^{2}, and 1 comes in front of y^{3}.

Thus: 1, 3, 3, 1.
         Answer Choice A
4 0
3 years ago
Read 2 more answers
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