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3 years ago

13

What is the equivalent fraction of 4/5

2 answers:

Aleks04 [339]3 years ago

4 0

Answer:

16/20

Step-by-step explanation:

Andre45 [30]3 years ago

4 0

4*4=16.
5*4=20.

Answer: 16/20.

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The loudness L(x) measured in decibels, of a sound of intensity x, measured in watts per square meter, is defined as L(x)=10 log

Margaret [11]

If you can find your way through all the smoke of the definition,
you find that an increase of 10 times the intensity is an increase
of 10 dB.

Next, if you can find your way over, under, around, and through
all the speeds and distances of the vehicles, you'll find that you
don't need them. Right in the middle of the pile, it says "intensity
10 times that of ...". That right there tells you that the sound of
the truck is 10 dB louder than the sound of the car.

So the car is 70 dB (asked for, and then given), and the truck is 80 dB.

4 0

3 years ago

Plsss anybody help no links more files they are viruses

mr_godi [17]

Answer:

1- B & C (Same answer and also I'm not that sure)

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8 0

3 years ago

Read 2 more answers

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

Which of the side lengths could form a triangle? A) 2 cm, 2 cm, 4 cm B) 3 cm, 5 cm, 10 cm C) 3 cm, 4 cm, 5 cm D) 4 cm, 8 cm, 15

Deffense [45]

The correct answer for USATesprep is

C) 3 cm, 4 cm, 5 cm

7 0

3 years ago

Read 2 more answers

At the movie theatre, child admission is $6.40 and adult admission is $9.90. On Friday, 154 tickets were sold for a total sales

Minchanka [31]

6.40x+9.90(154-x)=1230.90
Solve for x
X=84 for child

154-84=70 for adults

4 0

3 years ago