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Vikentia [17]
4 years ago
9

How many feet are in a yard

Mathematics
1 answer:
olasank [31]4 years ago
8 0

the answer 3                     














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What is this answer to this
Leviafan [203]
Your answer would be 14 and 2/3
4 0
3 years ago
Read 2 more answers
Help me please!!!!!!!!!!!
frozen [14]

Answer:

Step-by-step explanation:

Socratic had the answer on there I think

7 0
4 years ago
The perimeter of the rectangle playing field is 432 yards the length of the field is 4 yards less than triple the width The peri
seraphim [82]

Answer:

160 yards

Step-by-step explanation:

P=2l+2w

P=2(3w-8)+2(w)

432=2(3w-8)+2(w)

432=6w-16+2w

432=8w-16

432+16=8w

448=8w

w=448/8

w=56yards

l=3(56)-8

l=168-8=160yards

4 0
3 years ago
Find all solutions of the equation in the interval [0, 2pi).
natali 33 [55]

Answer:

Step-by-step explanation:

Begin by squaring both sides to get rid of the radical. Doing that gives you:

sin^2x=1-cosx

Now use the Pythagorean identity that says

sin^2x =1-cos^2x and make the replacement:

1-cos^2x=1-cosx. Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:

1-cos^2x+cosx-1=0 and then simplify to

cosx-cos^2x=0

Factor out the common cos(x) to get

cosx(1-cosx)=0 and there you have your 2 trig equations:

cos(x) = 0 and 1 - cos(x) = 0

The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at

x=\frac{\pi }{2},\frac{3\pi}{2}

The second equation simplifies to

cos(x) = 1

Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.

So, in the end, your 3 solutions are

x=\frac{\pi}{2},\pi,\frac{3\pi}{2}

8 0
3 years ago
The slope of a line is 1, and the y-intercept is -1. What is the equation of the line written in slope-intercept form?
scoray [572]

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have: m = 1 and b = -1. Substitute:

y = 1x - 1

<h3>Answer: y = x - 1</h3>
7 0
4 years ago
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