Answer:
no because they did not multiply the whole numbers and just multiplied the powers
Step-by-step explanation:
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Solution:
<u>Note that:</u>
- Given sentence: The difference between an integer p and (-5) is 1.
<u>Let's reread the sentence carefully.</u>
The difference between an integer p and (-5) is 1.
<u>Change the sign.</u>
<u>Subtract 5 both sides:</u>
- p + 5 = 1
- => p + 5 - 5 = 1 - 5
- => p = -4
x+3x+3x=21
7x=21
x=3
3, 9, 9=21
the answers are 3, 9, and 9
Răspunsul corect va fi numărul 4. Supãrat dacã meu vorbind nu este cel mai bun, vorbesc limba engleza. Dacă ai nevoie de numere consecutive, sunt 99, 102 şi 103.
