This is a polynomial of degree 4, because you have 4 roots real or imaginary:1st) x= 5 →(x-5)=0
2nd) x = - 3→(x+3) =0
3rd) x = -1+3i →(x+1-3i) = 0
and the 4th one that is not mentioned which is the conjugate of
-1+3i, that is -1-3i (in any polynomial if a root has the form of a+bi, there is always a conjugate root = a-bi)
4th) x= -1-3i→(x+1+3i) = 0
Hence the polynomial =(x-5)(x+3)((x+1-3i)(x+1+3i)
Solving the above will give you (unless I am mistaken, pls recalculate):
x⁴-9x²-50x-150<u />
Answer: B.
Step-by-step explanation:
Let's solve your system by elimination.
4x−2y=8;−2x+2y=6
Add these equations to eliminate y:
4x-2y=8
-2x+2y=6
2x=14
Substitute 7 for x in 4x−2y=8:
(4)(7)−2y=8
−2y+28=8 (Simplify both sides of the equation)
−2y+28+−28=8+−28 (Add -28 to both sides)
−2y=−20
−2y/−2=−20/−2 (Divide both sides by -2)
y=10
Answer:
It is a quadrilateral.
Step-by-step explanation:
Quadrilateral is a 4-sided shape where the total angles is 360°.
So when you add up all the angles, you will get 360°.
AABC has vertices at (1,5), (4,8), and (16, 12). A second triangle, ADEF, has vertices at (4, 20), (16, 32), and (64, 48). If th
navik [9.2K]
Answer: the first one
Step-by-step explanation:
(x,y)->(4x, 4y)
Answer:
i need more to answer the question
Step-by-step explanation:
