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3 years ago

40x + 60 = 20. what does x equal?

Mathematics

2 answers:

ollegr [7]3 years ago

8 0

Move all terms that don't contain x to the right side and solve.

x = -1

Elena-2011 [213]3 years ago

7 0

Subtract 60 on both sides to get -40.

You are left with 40x=-40

Divide both sides by 40 to leave x by itself.

You get x=-1.

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Abi invest€500 for 4 years in a bank account pays simple interest at a rate of 2.3% per year work out the total amount of the in

timofeeve [1]

Answer:

46euros

Step-by-step explanation:

Formula- I=P*R/100*T

P=principal amount R=rate T=time

Compute the values given in the question to this formula

So, it would be-

I= 500*0.023*4

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And that's all!

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3 years ago

What are perfect numbers between 1 and 28

snow_lady [41]

Answer:

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3 years ago

Find the radius of the cylinder when volume is 304 cm^3 and height is 10 cm

aleksandr82 [10.1K]

Answer:

solution,

Volume of cylinder=304 cm^3

height=10 cm

Radius=?

Now,

$volume = \pi {r}^{2} h \\ or \: 304 = 3.14 \times {r}^{2} \times 10 \\ or \: 304 = 31.4 \times {r}^{2} \\ or \: {r}^{2} = \frac{304}{31.4} \\ or \: {r}^{2} = 9.68 \\ or \: r = \sqrt{9.68} \\ or \: r = \sqrt{ {(3.11)}^{2} } \\ r = 3.11 \: cm$

Hope this helps..

Good luck on your assignment..

7 0

3 years ago

Please prove this........

Crazy boy [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

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3 years ago

Does 7.5 quarts =1 pint

Nataly_w [17]

No there are two pints in a quart

6 0

3 years ago

Read 2 more answers