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3 years ago

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Mathematics

1 answer:

andrew11 [14]3 years ago

7 0

Answer:

sorry

Step-by-step explanation:

I cant

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Which problem is modeled on the number line? 3+(-6) -3+(6) 3+6 -3+6

kramer

Answer:3+(-6)

Step-by-step explanation:

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3 years ago

2 Which of the following polynomials is not written in standard form?

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

Standard form is written in the order of the exponent on a variable from highest to lowest.

#1 exponents go 2, 1 , then zero. So, this is standard form.

#2 exponents go 2 then zero, so this is standard form.

#3 exponents go 1 then 2 then zero, so this is not in standard form.

#4 exponents go 3 to 2 to 1, so this is still in standard form.

hope this helps!

8 0

3 years ago

Natalie works in a doughnut shop. She packs doughnuts into boxes that each hold 12 doughnuts.

ehidna [41]

Answer:

Step-by-step explanation:

If each box holds 12 doughtnuts, and she packed a total of 1,272.

Then 1,272/12 is 16.

Therefore, she needs 16 boxes

4 0

3 years ago

Read 2 more answers

Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.

Dmitry [639]

Note that
$\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}$

Note that
$x= \frac{ \pi }{4}:\,\, sin(x) =cos(x)= \frac{1}{ \sqrt{2} },\,tan(x)=1\\x= \frac{7 \pi }{6} :\,\,sin(x)=- \frac{1}{2} ,\,\,cos(x)=- \frac{ \sqrt{3} }{2} ,\,\,tan(x)= \frac{1}{ \sqrt{3} }$

Use the identity
$tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

Therefore
$tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} = \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )} = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}$

Answer: 2 + √3

8 0

3 years ago

Verizon offers two billing plans for local calls. Plan 1 charges $30 per month for unlimited calls, and Plan 2 charges $11 per m

rodikova [14]

Answer:

Number of monthly calls = 475

Step-by-step explanation:

Given:

Plan 1 = $30 per month unlimited calls

Plan 2 = $11 + $0.04(per call)

Find:

Number of monthly calls, plan 1 better than plan 2

Computation:

Plan 1 (Cost) < Plan 2 (Cost)

30 < 11 + 0.04(x)

19 < 0.04(x)

475 < (x)

Number of monthly calls = 475

6 0

2 years ago