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astraxan [27]
3 years ago
7

Kevin is taking a two-part test in social studies

Mathematics
1 answer:
Phantasy [73]3 years ago
5 0

Answer:

He need to earn 32 points on part 2.

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Which set of ordered pairs could represent a linear function <br><br> (please help!!)
vlabodo [156]
The answer is A- (3,5), (5,1), (7,-2), (9,-6)
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Who can answer this question for me please
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Step-by-step explanation:

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The graph shows the height of a plant over time. What is the unit rate?
Anna35 [415]

Answer: unit rate = 1 / 5 = 0.2 inches per day

Step-by-step explanation:

The unit rate is the ratio that describes how one quantity changes as the other changes.You can find a unit rate from a graph the same way you find the slope.

1. Choose two points on the graph to find the slope

- (0,0) and (5,1)

  x₁ y₁        x₂ y₂  

2. Slope = y₂ - y₁ / x₂ - x₁   (This is essentially the change in y-coordinates divided by the change in x-coordinates.

unit rate = y₂ - y₁ / x₂ - x₁

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4 years ago
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The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c
Anestetic [448]

Answer:

a) The mean is \mu = 60

b) The standard deviation is \sigma = 9

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when X = 55.5, Z = -0.5

So

Z = \frac{X - \mu}{\sigma}

-0.5 = \frac{55.5 - \mu}{\sigma}

-0.5\sigma = 55.5 - \mu

\mu = 55.5 + 0.5\sigma

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when X = 71.52, Z = 1.28

So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{71.52 - \mu}{\sigma}

1.28\sigma = 71.52 - \mu

\mu = 71.52 - 1.28\sigma

Since we also have that \mu = 55.5 + 0.5\sigma

55.5 + 0.5\sigma = 71.52 - 1.28\sigma

1.78\sigma = 71.52 - 55.5

\sigma = \frac{(71.52 - 55.5)}{1.78}

\sigma = 9

\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60

Question

The mean is \mu = 60

The standard deviation is \sigma = 9

6 0
3 years ago
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