B. B+4
This should be right because if the brothers age is b and Jonna's age is 4 years older then it would be b+4
In order to isolate any term from an equation we need to clear out any different variable or numbers different from the one we want
![V=IR](https://tex.z-dn.net/?f=V%3DIR)
in this case I is being multiplied by R, so we need to do the opposite which is divide in order to eliminate
![V=\frac{IR}{R}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BIR%7D%7BR%7D)
But since this is an equality we must do it on both sides so de equation does not get altered
![\frac{V}{R}=\frac{IR}{R}](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7BR%7D%3D%5Cfrac%7BIR%7D%7BR%7D)
Then we simplify the equation
The simplest way to find the surface area of a cube is to multiply the length and the width.
In the table shown below:
Let N be the number of bottles filled,
Let T be the time in hours.
Given that the number of bottles filled is proportional to the amount of time the machine runs, we have
![\begin{gathered} N\propto T \\ \text{Introducing a proportionality constant, we have } \\ N\text{ = kT} \\ \Rightarrow k\text{ = }\frac{N}{T} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20N%5Cpropto%20T%20%5C%5C%20%5Ctext%7BIntroducing%20a%20proportionality%20constant%2C%20we%20have%20%7D%20%5C%5C%20N%5Ctext%7B%20%3D%20kT%7D%20%5C%5C%20%5CRightarrow%20k%5Ctext%7B%20%3D%20%7D%5Cfrac%7BN%7D%7BT%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Let's evaluate the value of k for each day.
Thus, on monday,
![\begin{gathered} N\text{ = 9900} \\ T\text{ = 5.5} \\ \text{thus,} \\ k\text{ = }\frac{9900}{5.5} \\ \Rightarrow k\text{ = 1800} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20N%5Ctext%7B%20%3D%209900%7D%20%5C%5C%20T%5Ctext%7B%20%3D%205.5%7D%20%5C%5C%20%5Ctext%7Bthus%2C%7D%20%5C%5C%20k%5Ctext%7B%20%3D%20%7D%5Cfrac%7B9900%7D%7B5.5%7D%20%5C%5C%20%5CRightarrow%20k%5Ctext%7B%20%3D%201800%7D%20%5Cend%7Bgathered%7D)
Tuesday:
![\begin{gathered} N\text{ = }11160 \\ T\text{ = }6.2 \\ \text{thus,} \\ k\text{ = }\frac{11160}{6.2} \\ \Rightarrow k\text{ = 1800} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20N%5Ctext%7B%20%3D%20%7D11160%20%5C%5C%20T%5Ctext%7B%20%3D%20%7D6.2%20%5C%5C%20%5Ctext%7Bthus%2C%7D%20%5C%5C%20k%5Ctext%7B%20%3D%20%7D%5Cfrac%7B11160%7D%7B6.2%7D%20%5C%5C%20%5CRightarrow%20k%5Ctext%7B%20%3D%201800%7D%20%5Cend%7Bgathered%7D)
Wednesday:
![\begin{gathered} N\text{ = }12330 \\ T\text{ = }6.25 \\ \text{thus,} \\ k\text{ = }\frac{12330}{6.25} \\ \Rightarrow k\text{ = 1972.8} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20N%5Ctext%7B%20%3D%20%7D12330%20%5C%5C%20T%5Ctext%7B%20%3D%20%7D6.25%20%5C%5C%20%5Ctext%7Bthus%2C%7D%20%5C%5C%20k%5Ctext%7B%20%3D%20%7D%5Cfrac%7B12330%7D%7B6.25%7D%20%5C%5C%20%5CRightarrow%20k%5Ctext%7B%20%3D%201972.8%7D%20%5Cend%7Bgathered%7D)
Thursday:
![\begin{gathered} N\text{ = }10440 \\ T\text{ = }5.80 \\ \text{thus,} \\ k\text{ = }\frac{10440}{5.8} \\ \Rightarrow k=1800 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20N%5Ctext%7B%20%3D%20%7D10440%20%5C%5C%20T%5Ctext%7B%20%3D%20%7D5.80%20%5C%5C%20%5Ctext%7Bthus%2C%7D%20%5C%5C%20k%5Ctext%7B%20%3D%20%7D%5Cfrac%7B10440%7D%7B5.8%7D%20%5C%5C%20%5CRightarrow%20k%3D1800%20%5Cend%7Bgathered%7D)
It is observed that all exept wednesday have the same value of k.
Thus, the amount of time required for the number of bottles filled on wednesday is evaluated as
![\begin{gathered} N\text{ = }12330 \\ k\text{ = 1800} \\ T\text{ = ?} \\ \text{but} \\ k\text{ = }\frac{N}{T} \\ 1800\text{ = }\frac{12330}{T} \\ \Rightarrow T\text{ = }\frac{\text{12330}}{1800} \\ T\text{ = 6.85} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20N%5Ctext%7B%20%3D%20%7D12330%20%5C%5C%20k%5Ctext%7B%20%3D%201800%7D%20%5C%5C%20T%5Ctext%7B%20%3D%20%3F%7D%20%5C%5C%20%5Ctext%7Bbut%7D%20%5C%5C%20k%5Ctext%7B%20%3D%20%7D%5Cfrac%7BN%7D%7BT%7D%20%5C%5C%201800%5Ctext%7B%20%3D%20%7D%5Cfrac%7B12330%7D%7BT%7D%20%5C%5C%20%5CRightarrow%20T%5Ctext%7B%20%3D%20%7D%5Cfrac%7B%5Ctext%7B12330%7D%7D%7B1800%7D%20%5C%5C%20T%5Ctext%7B%20%3D%206.85%7D%20%5Cend%7Bgathered%7D)
Hence, the incorrect day is Wednesday. The amount of time for that many bottles should be 6.85 hours.
Answer:
π/8 radians
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION
In 1 h the minute hand on a clock moves through a complete circle, and the hour hand moves through 1 12 of a circle. Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)?
SOLUTION
✓If the minute hand on a clock moves through complete circle in 1 hour, then it means that it goes through a circle and angle of circle in radians is 2π.
Between 1:00 p.m. and 1:45pm in the same day we have 45 minutes i.e (1.45 pm -1pm)
Within the 1hour minutes, the hand can move with complete cycle of 2π radians
Then At time t= 45minutes
Angle through the circle at 45 minutes= 45/60 ×2π radians
= 3π/2 radians
And if the hour hand goes through a complete cycle 1/12 as told in the question we have 1/2 × 2π radians
For t=45 minutes
Then 1/12 × 2π ×45/60
= π/8 radians
Hence, the minute hand and the hour hand move π/8 radians between 1:00 p.m. and 1:45 p.m.