1. We we can split 4p into 9p - 5p, and now we have 3p² + 9p - 5p - 15 = 0. We can take out 3p from the first 2 terms and -5 from the last 2 terms. This gets us 3p (p + 3) -5 (p + 3) = 0. These two terms have (p + 3) as a common facor, so we can take that out as well, which give us (p + 3)(3p - 5) = ). Using Zero Product Property, p + 3 = 0 and 3p - 5 = 0, and when we solve each equation, we get p = -3, p= 5/3.

2. We will use the same process.

6x² + 14x - 3x - 7 = 0

2x (3x+7) - 1 (3x+7) = 0

(3x + 7)(2x - 1) = 0

3x + 7 = 0, 2x - 1 = 0

x = -7/3, x=1/2

Hope this helps!

4 0

3 years ago

Katy is on a path, moving towards a bridge. The given table represents a function that describes Katy’s distance from the bridge

Sophie [7]

Answer:

D : Katy was 300 meters from the bridge, and it took her 6 minutes to reach the bridge.

Step-by-step explanation:

Recall that x represents the time walked

When you see the first entry on the table as: x=0, that means Katy is about to start her walk, and the value to the right which represents her distance from the bridge is 300 meters. So as her walk started she was 300 meters from the bridge.

Now look at the last entry pair at the bottom of the table: the value in the "x" column (that represents the number of minutes she walked) reads: 6, and the value to the right (next column) reads 0 (0 meters from the bridge)

This is telling us that Katy was at the bridge after 6 minutes of walk. So answer D is the correct answer representing the given table of time and distance values.

3 0

3 years ago

Hey what's the answer <img src="https://tex.z-dn.net/?f=%20-%2011a%283a%20%2B%202a%29" id="TexFormula1" title=" - 11a(3a + 2a

allsm [11]

Answer:

$- 11a(3a + 2b) \\ = - 11 \times 3 \times a \times a + ( - 11 \times 2 \times a \times a) \\ = - 33 {a}^{2} - 22ab$