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3 years ago

You find a mutual fund that offers approximately 8.5% APR compounded

Mathematics

2 answers:

Usimov [2.4K]3 years ago

7 0

Answer:459.27

Step-by-step explanation:

lidiya [134]3 years ago

5 0

Answer D. 459.27:

Step-by-step explanation:

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I need help on this question, think any of you guys could help?

levacccp [35]

Answer:

We need to find the circumference, and in order to find the circumference we must know the formula for it.

Formula for circumference of a circle;

a = 2πr

Where π is the pi(3.14 or 22/7), and r is the radius which is half of the diameter.

Since we are given the diameter, we need to find the radius. So 1/2 of the diameter (26 x 1/2) = is 13

Now we just plug in the actual values in the formula:

a = 2πr

a = 2 x 3.14 x 13

a = 18.84 feet

But now, we need to find how many revolutions it would take to get to 500 feet.

So we divide 500 feet by 18.84 feet;

500/18.84 = 26.53, around 27 revolutions.

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2 years ago

Which subtraction problem does NOT require zero pairs to solve using chips ? ( PLEASE ANSWER ASAP )

Mama L [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

Help! Exponential Equation WITHOUT CALCULATOR

ale4655 [162]

$
1.
(2^{x} -2^{-x})^{2} = 4^{2} \\ \\2^{2x}-2*2^{x}*2^{-x} + 2^{-2x} =4^{2} \\ \\2^{2x}-2*2^{x-x} + 2^{-2x} =4^{2} \\ \\ 2^{2x}+ 2^{-2x} - 2=16 \\ \\ 2^{2x}+ 2^{-2x} = 18

\\ \\ 2.( 2^{x})^{3} - (2^{-x}^) ^{3}= (2^{x} -2^{-x})(2^{2x}+2^{x}*2^{-x}+2^{-2x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+2^{x}*2^{-x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+1)
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})((2^{2x}+2^{-2x})+1)
$

$\\ \\ ( 2^{x})^{3} - (2^{-x})^{3} =(4)((18)+1)= 76
\\ \\ 2^{3x}-2^{-3x} =76
$

4 0

3 years ago

Which of the following equations could be solved for a radius? Select all that apply.

zalisa [80]

Answer:

A = π · (r²)

Step-by-step explanation:

$A =$ π · r² is the area of a circle.

While π · r² · h can also give you the radius, it can only do so for the Volume $V$ , not the Area $A$ .

$V=lwh$ doesn't really apply for a circular object, as it requires the length and width. For circular objects, both are equal to the diameter of the object, and 2² · r² · h does not equal the Volume.

$V=$ π · r³ seems awfully like the volume of a sphere, but there's something missing. The true volume of a sphere is $V=\frac{4}{3}$ · π · r³, not $V=$ π · r³.

$A=\frac{1}{2}*b*h$ only applies for triangles.

3 0

2 years ago

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What is the answer for question 4? WHO EVER ANSWER'S IT IS THE BRAINIEST

balandron [24]

The answer is sunlight.

8 0

2 years ago