Consider two triangles AEB and CEF. In these triangles:
Thus, by AAA theorem,
Corresponding sides of similar triangles are proportional, then
ABCD is a parallelogram, then AB=CD.
Therefore,
CD=2CF and CD=DF+CF. Equate these two expressions:
DF+CF=2CF,
DF=CF.
This gives you that DF:CF=1:1.
Answer: 1:1
Answer:
log 3(x+4) = log 3 + log (x+4)
Step-by-step explanation:
Because 3(x+4) is a product, log 3(x+4) = log 3 + log (x+4).
87
Hope this helps