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Klio2033 [76]
3 years ago
8

Find the value of X . Round answer to nearest tenth.

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:

Step-by-step explanation:

From the given right angle triangle,

The hypotenuse of the right angle triangle is the unknown side.

With m∠x as the reference angle,

the adjacent side of the right angle triangle is 17

the opposite side of the right angle triangle is 16

To determine x, we would apply

the tangent trigonometric ratio which is expressed as

Tan θ, = opposite side/adjacent side. Therefore,

Tan x = 16/17 = 1.0625

x = Tan^-1(0.941)

x = 43.3° to the nearest tenth.

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0.11111111, 0.33333333, 0.556

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A) 1 divided by 9=0.11111111

B) 3 divided by 9=0.33333333

C)5 divided by 9= 0.556

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What is the value of 12/n when N=2
Maksim231197 [3]

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4 years ago
(b) The table below indicates the cost of certain air tel kiosk Z 0.15 0.20 0.25 0.75 0.80 0.85 1.85 1.90 1.95 2.00 2.05 QZ 0.05
marshall27 [118]

Using the normal distribution, it is found that there is a

a) 0% probability that the number of calls received at the switchboard will be exactly 578.

b) 0.1586 = 15.86% probability that the number of calls received at the switchboard will be less than 570.

c) 0.9485 = 94.85% probability that the number of calls received at the switchboard will be between 561 and 600.

<h3>Normal Probability Distribution</h3>

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 580, hence \mu = 580.
  • The standard deviation is of 10, hence \sigma = 10.

Item a:

In the normal distribution, the probability of an exact value is 0%, hence, 0% probability that the number of calls received at the switchboard will be exactly 578.

Item b:

The probability is the <u>p-value of Z when X = 570</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{570 - 580}{10}

Z = -1

Z = -1 has a p-value of 0.1586.

0.1586 = 15.86% probability that the number of calls received at the switchboard will be less than 570.

Item c:

This probability is the <u>p-value of Z when X = 600 subtracted by the p-value of Z when X = 561</u>, hence:

X = 600:

Z = \frac{X - \mu}{\sigma}

Z = \frac{570 - 580}{10}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 561:

Z = \frac{X - \mu}{\sigma}

Z = \frac{561 - 580}{10}

Z = -1.9

Z = -1.9 has a p-value of 0.0287.

0.9772 - 0.0287 = 0.9485.

0.9485 = 94.85% probability that the number of calls received at the switchboard will be between 561 and 600.

You can learn more about the normal distribution at brainly.com/question/24663213

8 0
2 years ago
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