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3 years ago

Which choice shows a correct way to find 6 × 3 × 5?

Mathematics

2 answers:

Jet001 [13]3 years ago

8 0

Answer:

Step-by-step explanation:

Vinvika [58]3 years ago

3 0

6x(3x5)

hope this helped!

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I needs some help pls

GrogVix [38]

Here is the order

- 6 2/3 ,- 1.3 , 29/8 , 7

5 0

3 years ago

How to do this in a 6th grade way

il63 [147K]

Answer:

4 2/3 - 1 2/3 and just keep doing that until you get to 0 it would take 3 days

Step-by-step explanation:

4 2/3 - 1 2/3=3

3- 1 2/3= 1 1/3

1 1/3- 1 2/3 = -1/3

6 0

3 years ago

Explain the steps necessary to convert a quadratic function in standard form to vertex form

SIZIF [17.4K]

Answer:

See below.

Step-by-step explanation:

Here's an example to illustrate the method:

f(x) = 3x^2 - 6x + 10

First divide the first 2 terms by the coefficient of x^2 , which is 3:

= 3(x^2 - 2x) + 10

Now divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form

(x - b/2)^2 - b/2)^2 (where b = 2) , which will be equal to x^2 - 2x in a different form.

= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x + 1^2 and we have to make it equal to x^2 - 2x)

= 3 [(x - 1)^2 -1 ] + 10

= 3(x - 1)^2 - 3 + 10

= 3(x - 1)^2 + 7 <------- Vertex form.

In general form the vertex form of:

ax^2 + bx + c = a [(x - b/2a)^2 - (b/2a)^2] + c .

This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.

3 0

3 years ago

Read 2 more answers

a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect

PolarNik [594]

Number of dimes were 81 and number of quarters were 47

Solution:

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that There are 128 coins in all

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

Also given that collection of dimes and quarters is worth $19.85

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

$d \times 0.10 + q \times 0.25 = 19.85$

0.1d + 0.25q = 19.85 -------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 128 - q -------- eqn 3

Substitute eqn 3 in eqn 2

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

Thus number of dimes were 81 and number of quarters were 47

4 0

3 years ago

Pls help me I don't understand!!!!!!!!

jeka57 [31]

Answer:

X=SMALL BOX.

Y=LARGE BOX

THEREFORE,X+Y=21

X=21-Y

THEREFORE,25(21-Y)+70Y=1110 POUNDS

525-25Y+70Y=1110

525+45Y=1110

45Y=1110-525

45Y=585

Y=585/45

Y=13 .

Therefore,13 large box and8 small box..

3 0

3 years ago

Read 2 more answers