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3 years ago

What's 43 centimeters in fraction

1 answer:

8 0

Well There are 100 centimeters in 1 meter, so 43cm equals 43/100m.

Hope this helps

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A political polling agency predicts candidate A will win an election with 63% of the votes. Their poll has a margin of error of

scoray [572]

Answer:

56% ≤ p ≤ 70%

Step-by-step explanation:

Given the following :

Predicted % of votes to win for candidate A= 63%

Margin of Error in prediction = ±7%

Which inequality represents the predicted possible percent of votes, x, for candidate A?

Let the interval = p

Hence,

|p - prediction| = margin of error

|p - 63%| = ±7%

Hence,

Upper boundary : p = +7% + 63% = 70%

Lower boundary : p = - 7% + 63% = 56%

Hence,

Lower boundary ≤ p ≤ upper boundary

56% ≤ p ≤ 70%

5 0

4 years ago

Determine whether GHI is a right triangle for the given vertices G(2,7) H(3,6), I(-4,-1)

kotegsom [21]

No it's an acute triangle.

5 0

3 years ago

Margaret has $200 in her savings account. She will save $50 more dollars each week and not take any money out of the account. Wh

Ad libitum [116K]

Option one because it’s going up by 50 and it’s also showing that she’s starting with the 200$ she already had

4 0

3 years ago

HELP ASAP HELP ASAP HELP ASAP HELP ASAP

adell [148]

It’s the second, the penultimate and the last one :)

3(2 + x)
x + 2x + 2 + 4
x + x + x + 1 + 1 + 1 + 1 + 1 + 1

5 0

2 years ago

Read 2 more answers

so, I need to just find the missing length, if you can, please explain the pythagorean theorem to find the missing side. I don't

ANTONII [103]

The surface area of the triangular prism is 828 in².

Solution:

Let the missing length of the triangle be x.

Using Pythagoras theorem,

In right triangle, square of the hypotenuse is equal to the sum of the squares of other two sides.

$12^2+x^2=15^2$

$144+x^2=225$

Subtract 144 on both sides of the equation.

$x^2=225-144$

$x^2=81$

Taking square root on both sides, we get

x = 9

The missing length of the triangle is 9 in.

Area of the front triangle = $\frac{1}{2}\times 12\times 9$

= 54 in²

Area of the back triangle = $\frac{1}{2}\times 12\times 9$

= 54 in²

Area of the sloping rectangle = 20 × 9

= 180 in²

Area of the back rectangle = 20 × 12

= 240 in²

Area of the base rectangle = 20 × 15

= 300 in²

Total area = 54 in² + 54 in² + 180 in² + 240 in² + 300 in²

= 828 in²

The surface area of the triangular prism is 828 in².

4 0

3 years ago