Answer:
Thus, the two root of the given quadratic equation
is 5.24 and 0.76 .
Step-by-step explanation:
Consider, the given Quadratic equation, 
This can be written as , 
We have to solve using quadratic formula,
For a given quadratic equation
we can find roots using,
...........(1)
Where,
is the discriminant.
Here, a = 1 , b = -6 , c = 4
Substitute in (1) , we get,





and 
We know
(approx)
Substitute, we get,
(approx) and
(approx)
(approx) and
(approx)
Thus, the two root of the given quadratic equation
is 5.24 and 0.76 .