Derslerinde başarılar dilerim
Answer:
29 small boxes
Step-by-step explanation:
Answer:
the correct answer is D...
The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.
Given a company has 200 machines. Each machine has a 12% probability of not working.
If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.
So
1) probability that 5 would not be working
C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵
≈ 0.18665
2) probability that at least one machine would be working
0.88⁴⁰ ≈ 0.00602
3) probability that all would be working
1 - 0.12⁴⁰ ≈ 1.0000
Learn more about probability here: brainly.com/question/24756209
#SPJ10
Answer:
The answer is D
Step-by-step explanation:
The solution would be like this for this specific problem:
Cost of the computer:
i = 0.117 / 12
i = 0.00975
= monthly payment
= (i * P * (1 + i)^n) / ((1 + i)^n - 1)
= (0.00975 * $1433 * (1 + 0.00975)^30) / ((1 + 0.00975)^30 - 1)
= $55.32
Electricity cost:
= $0.79 * 365.25 * 7
= $2019.83
Electricity Percentage:
= $2019.83 / ($2019.83 + $1659.60)
= 54.89%
Electricity:
= ($0.79 * 365 * 5) + ($0.79 * 366 * 2)
= $2020.03
Electricity Percentage:
= $2020.03 / ($2020.03 + $1659.60)
= 54.898%
In total, the electricity made up 54.898% of the lifetime cost of the computer.
