What is speed of bobsled whose distance time graph indicates that it traveled 122m in 25 s

Explain how the situation described in the article shows that the outside environment can help and hurt cells

jeka57 [31]

Answer: An external factor caused damage to the nerve cells. However, the injection of new cells into the injured area prompted a beneficial change. The injured cells received proteins that decreased inflammation and pain in the mice.

7 0

3 years ago

Describe in detail how gases are exchanged between the respiratory system and the circulatory system in the lungs

charle [14.2K]

Answer:

Gas exchange

Explanation:

Gas exchange takes place in the millions of alveoli in the lungs and the capillaries that envelop them. As shown below, inhaled oxygen moves from the alveoli to the blood in the capillaries, and carbon dioxide moves from the blood in the capillaries to the air in the alveoli.

4 0

3 years ago

The process of bones increasing in thickness is known as ________.

ololo11 [35]

Answer:

The cells lying in the deeper layer of periosteum are known as osteoblasts (bone forming cells). These cells divide continuously and form the osteocytes, thus increase the thickness of bone. ... The process of reshaping the bone is called remodeling and it is one of the major factors responsible for increasing size of marrow cavity.

5 0

3 years ago

Using the dichotomous key, which class does this animal belong to?

JulijaS [17]

The answer is a Reptile.

Because it lives in water (also out) and has rough skin.

4 0

3 years ago

Read 2 more answers

How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C

fenix001 [56]

Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios) for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3' NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3' NO STOP CODON

5'... CTT ACA GTT TAT TGA TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG TAA G

4)Now you need to find start (AGT in terms of DNA) and stop codons(TAA, TAG, TGA, also in terms of DNA), in 5->3 and de reverse complementary.

As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

8 0

3 years ago