<span>Given cotA + cotB + cotC = sqrt3
to prove triangle ABC is equilateral
we prove this by assuming ABC to be equialteral and establishing the truth
of the statement cotA + cotB + cotC =sqrt3
since ABC is equialteral angleA=angleB=angleC=60 degrees
cotA=cotB=CotC = cot60= 1/sqrt3
therefore cotA + cotB + cotC = 1/sqrt3 + 1/sqrt3 + 1/sqrt3
=3/sqrt3
=sqrt3 which is equal to the RHS ( right hand side) of the expression
hence our assumption that ABC is equilateral is true</span>
The answer to this problem is 1463
The given quadratic equation will not have any real solution for c<-9/4.
The given quadratic equation is:

<h3>What is a quadratic equation?</h3>
Any equation of the form
is called a quadratic equation with a≠0.
In order to have no real solution, the discriminant of a quadratic equation will be less than zero.




For
the given quadratic equation will have no real solutions.
Hence, the given quadratic equation will not have any real solution for c<-9/4.
To get more about quadratic equations visit:
brainly.com/question/1214333
Answer:
17m
(Anyone can correct me if I'm wrong)
Step-by-step explanation:
The following equation would be used: 
We would simply substitute the given values, move the values around then we would get our answer:
