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Pani-rosa [81]
3 years ago
6

6x + 11 = 21 Help I’m on a quiz and this question is so confusing

Mathematics
1 answer:
Westkost [7]3 years ago
3 0

Answer:

Step by Step Solution

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    6*x+11-(21)=0  

Step by step solution :

STEP

1

:

Pulling out like terms

1.1     Pull out like factors :

  6x - 10  =   2 • (3x - 5)  

Equation at the end of step

1

:

STEP

2

:

Equations which are never true:

2.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

2.2      Solve  :    3x-5 = 0  

Add  5  to both sides of the equation :  

                     3x = 5

Divide both sides of the equation by 3:

                    x = 5/3 = 1.667

One solution was found :

x = 5/3 = 1.667

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The number (x) that is (=) 10 less than (-) 6

x = 6 - 10   Subtract
x = -4


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I need help on the top one 25 pts
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The answer to the question

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Expand the following.<br> (3x + 2)2<br> A.9x2+6x+4<br> B.9x2+4<br> C.3x2+4<br> E.9x2+12x+4
PolarNik [594]

Step-by-step explanation:

E

working ;

(3x+2)^2

*Apply Perfect Square Formula : (a+b) =a^2+2ab+b^2

a = 3x,b = 2

(3x)^2 + 3x.2+2^2

finally Answer is:

= 9x^2 + 12x +4

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2 years ago
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Answer:

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8 0
3 years ago
the length of a rectangle exceeds its width by 6 inches and the area is 40 square inches. What are the length and width of the r
Lorico [155]

Classic Algebra and its unnecessarily complicated sentence structure. As you may have probably known, Algebra has its own "vocabulary set".


"the length of a rectangle exceeds its width by 6 inches" -> length is 6 in. longer than width -> l= w + 6


Since we're solving for the length and width, let's give them each variables.

length = l = w+6

width = w


The next bit of information is "the area is 40 square inches"

Applying the formula for the area of a rectangle we can set up:

l x w = 40

replace "l", or length, with it's alternate value.

(w+6) x w = 40

distribute

w^{2} + 6w = 40

subtract 40 from both sides

w^{2} + 6w - 40 = 0

factor

(w - 4)(w + 10) = 0

solve for w

w= 4, or -10


So great, we have 2 values; which one do we choose? Since this problem is referring to lengths and inches, we will have to choose the positive value. There is not such thing as a negative distance in the real world.


We now have half of the problem solved: width. Now we just need to find the length which we can do but substituting it back into the original alternate value of l.


l = w + 6

w=4

l = 4 + 6 = 10


The length is 10 in. and the width is 4 in. Hope this helps!

8 0
3 years ago
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