3x^3+0x^2-2x+k:x-2=3x^2+6x+10
3x^2-6x^2
6x^2-2x
6x^2-12x
10x+k
10x-20
k+20
Thus k=-20
Hey! the answer is 6. you have to take the 36 over to the other side which will be 36 obviously and than your left with x to the 2nd and than you will square root 36 to get rid of the squared number and than it’s 6
First we need to calculate t(4) because x=4 for 4 shifts.
t(4) = 4*4 +3 = 19
Now because function "c" is declared as c(t(x)) for value x=4 we are searching c(19)! because t(4) = 19
c(19) = 2*19 + 5 = 43.
Answer is 43
2^2. 2 and 2. Because 2 and 2
Answer:
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