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xxTIMURxx [149]
3 years ago
8

How can I solve 8 5/6 - 2 1/3=

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
6 0
There is another method than what the other user has pointed out (both are valid and are up to personal preference as to which are better)

For this method you need to make sure that both the denominators are the same.

(See attached image)

I hope this makes sense!

As a summary; you must make sure that both denominators of the fractions are the same. Whatever number you multiply by for the denominator, use also for the numerator.

rusak2 [61]3 years ago
3 0
You turn 8 5/6 and 2 1/3 into improper fractions (8 5/6 becomes 53/6 and 2 1/3 becomes 7/3)

Then you take 53/6 and 7/3 and find a common denominator which is 6
Then you multiply 7x2 and 3x2 which equals to 14/6

53/6 - 14/6 is 39/6
You can leave it as 39/6 or change it into a mixed number, if you make it a mixed number then you would get 6 3/6 which is equivalent to 6 1/2.
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Which expression represents -3/4 and -0.2 on a number line
olga_2 [115]

Step-by-step explanation:

Plot -3/4 in between -1/2 and -1

Plot -0.2 in between -0.3 and -0.1 or between -2/5 and 0.

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3 years ago
Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

8 0
3 years ago
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