2 years ago

An example of a false and a true equation

Mathematics

2 answers:

lara31 [8.8K]2 years ago

7 0

True equation

2+3 =5

False equation

2+2 = 6

Gnom [1K]2 years ago

4 0

True equation
6-3=3
False equation
6-3=5

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Add the product of 5 and 6 with the product of 3 and 7

xz_007 [3.2K]

It is 51.

5x6=30

3x7=21

30+21=51

Hope that I was of help.

5 0

2 years ago

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Pwease help me anyone. thanks :-) :-) :-) :-) :-) :-) :-) :-)!!!!

adell [148]

A)
$x+3$

b)
$x(x+3)=340\\
x^2+3x-340=0$

c)
$x(x+3)=340\\ x^2+3x-340=0\\
\Delta=3^2-4\cdot1\cdot(-340)=9+1360=1369\\\sqrt{\Delta}=37\\
x_1=\dfrac{-3-37}{2}=-20\\
x_2=\dfrac{-3+37}{2}=17$

It's 17.

3 0

3 years ago

HELP ALL MY POINTSwhich expression is equivilent to -6(-2/3+2x)

Andrews [41]

Answer:

Step-by-step explanation:

4 0

3 years ago

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C. Mrs. Hampton used 1/3 of a gallon of milk to feed three kittens. If she fed an equal amount

tatyana61 [14]

1/9 I hope this helps you out!

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2 years ago

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Select True or False for each statement.

SSSSS [86.1K]

$\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32$

TRUE

$\sqrt[5]{36^4}=36^{4/5}$

which surely isn't 36. FALSE

$\sqrt{12} - \dfrac 2 5 \sqrt{75} = 2 \sqrt{3} -\dfrac 2 5 (5) \sqrt{3} = 0$

FALSE

For the fourth one we have a

$\sqrt{98b} + \sqrt{2b}$

which isnt

$10\sqrt{b}$

so this is FALSE.

$\dfrac{1}{(\sqrt 5 - \sqrt 6)^2}$

$= \dfrac{1}{(\sqrt 5 - \sqrt 6)^2} \cdot \dfrac{(\sqrt 5 + \sqrt 6)^2}{(\sqrt 5 + \sqrt 6)^2}$

$= \dfrac{(\sqrt 5 + \sqrt 6)^2}{ ( (\sqrt 5 - \sqrt 6)(\sqrt 5 + \sqrt 6))^2}$

$= \dfrac{(\sqrt 5 + \sqrt 6)^2}{( 5-6)^2}$

$=(\sqrt 5 + \sqrt 6)^2$

No fractions in that one so FALSE.

3 0

2 years ago