Answer:
True
Step-by-step explanation:
A linear equation cannot be used.
because 60/1 isn't equal to 70/5 and isn't equal to 80/20 and so on.
Yes it can. It doesn't <em>have to be</em>, but it can be without too much trouble.
In fact, ALL rhombuses are quadrilaterals.
Use mathpapa.com or cymath.com
Answer:
the probability that a code word contains exactly one zero is 0.0064 (0.64%)
Step-by-step explanation:
Since each bit is independent from the others , then the random variable X= number of 0 s in the code word follows a binomial distribution, where
p(X)= n!/((n-x)!*x!*p^x*(1-p)^(n-x)
where
n= number of independent bits=5
x= number of 0 s
p= probability that a bit is 0 = 0.8
then for x=1
p(1) = n*p*(1-p)^(n-1) = 5*0.8*0.2^4 = 0.0064 (0.64%)
therefore the probability that a code word contains exactly one zero is 0.0064 (0.64%)
