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skelet666 [1.2K]
3 years ago
9

Find the Inverse of 3x^3-1=y

Mathematics
1 answer:
Anika [276]3 years ago
5 0
y = 3x^{3} - 1
x = 3y^{3} - 1
3y^{3} = x + 1
y^{3} = \frac{x + 1}{3}

y = \sqrt[3]{\frac{x + 1}{3}}
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