Question

Find the Inverse of 3x^3-1=y

Answer 1

$y = 3x^{3} - 1$
$x = 3y^{3} - 1$
$3y^{3} = x + 1$
$y^{3} = \frac{x + 1}{3}$

$y = \sqrt[3]{\frac{x + 1}{3}}$