Rearrange slightly...
12xy-8y-9x+6 now factor 1st and 2nd pair of terms
4y(3x-2)-3(3x-2)
(4y-3)(3x-2)
<span>Given the two end of the diameter of the circle, we are able to compute the center of the circle as 0.5*[(-1,3)+(7,-7)]=(3,-2). The radius of the circle is 0.5*sqrt[(-1-7)^2+(3+7)^2]=sqrt(41). Therefore the equation of the circle is (x-3)^2+(y+2)^2=41.</span>
Carlos is correct
Since we don't know the length of sides PR and XZ, the triangles can't be congruent by the SSS theorem or the SAS theorem, and since we don't know the measure of angles Y and Q, the triangles can't be congruent by the ASA theorem, the SAS theorem or the AAS theorem. Therefore, Carlos is correct.
Carlos is correct. Since the angles P and X are not included between PQ and RQ and XY and YZ, the SAS postulate cannot be used, since it states that the angle must be included between the sides. Unlike with ASA, where there is the AAS theorem for non-included sides, there is not SSA theorem for non-included angles, so the triangles cannot be proven to be congruent.
Answer:
-1.5
Step-by-step explanation:easy
Answer:
6.50
Step-by-step explanation: